2016-06-28 159 views
2

我使用Java創建比較數據A和每個數據。如何將Json字符串轉換爲List <HashMap <String,String >>?

首先,我從txt文件(文件中的數組類型)提取了數組數據。

其次,我的數據庫中有一個Json字符串數據(MySQL列類型:JSON)。

我分析txt文件,並列出

FileInputStream fstream = new FileInputStream(Path); 
List<HashMap<String, String>> list = list(fstream); 

public List<HashMap<String, String>> list(FileInputStream fstream) { 
    BufferedReader buff = new BufferedReader(new InputStreamReader(fstream)); 
    List<HashMap<String, String> list = new ArrayList<>(); 

    try { 
    while ((strLine = buff.readLine()) != null) { 
     s = strLine.split(" "); 
     HashMap<String, String> map = new HashMap<>(); 
     pts = s[4].split(":")[1]; 
     ptstime = s[5].split(":")[1]; 
     map.put("pts", pts); 
     map.put("ptstime", getDurationString(ptstime)); 
     if (pts_itv.equals("0") && ptstime_itv.equals("00:00")) { 
     map.put("pts_itv", "0"); 
     map.put("ptstime_itv", "00:00"); 
     } 
     else { 
     map.put("pts_itv", String.valueOf(Long.parseLong(pts) - Long.parseLong(pts_itv))); 
     map.put("ptstime_itv", getDurationString(String.valueOf(String.format("%.4f", Double.parseDouble(ptstime) - Double.parseDouble(ptstime_itv))))); 
     } 
     pts_itv = pts; 
     ptstime_itv = ptstime; 
     list.add(map); 
    } 
    } 
    catch (IOException ex) { 
     LOG.error("ERROR : " + ex.getLocalizedMessage() + ", " + ex.getMessage()); 
    } 
    finally { 
    try { 
     buff.close(); 
    } catch (IOException ex) {} 
    } 
    return list; 
} 

提取數據

[{pts_itv=0, ptstime=00:00:00.112792, pts=2707, ptstime_itv=00:00}, {pts_itv=192192, ptstime=00:00:08.12079, pts=194899, ptstime_itv=00:00:08.80}, {pts_itv=128128, ptstime=00:00:13.4595, pts=323027, ptstime_itv=00:00:05.3387}, {pts_itv=277277, ptstime=00:00:25.127, pts=600304, ptstime_itv=00:00:11.5532}] 

我能得到索引鍵對象鍵。

list.get(0).get("pts_itv"); 

和第二數據(SELECT查詢從MySQL(JSON列型))

rs = Web.getInstance().getList(idx); //get data by sql query 
jObj = (JSONObject) new JSONParser().parse(rs); 
jArr = (JSONArray) jObj.get("data"); 
for (int i = 0; i < jArr.size(); i++) { 
    JSONObject Jarr = (JSONObject) jArr.get(i); 
    System.out.println(Jarr.get("PtsData")); 
} 

PtsData是

[{"pts": "81831", "pts_itv": "0", "ptstime": "00:00:03.40963", "ptstime_itv": "00:00"}, {"pts": "127877", "pts_itv": "46046", "ptstime": "00:00:05.32821", "ptstime_itv": "00:00:01.9186"}, {"pts": "157907", "pts_itv": "30030", "ptstime": "00:00:06.57946", "ptstime_itv": "00:00:01.2512"}] 
java.lang.String 

我想PtsData轉換爲第一數據類型。我如何將PtsData轉換爲List類型?

+1

使用[jackson](https://github.com/FasterXML/jackson)或[Gson](https://github.com/google/gson) – Sampada

+0

謝謝Sampada。我解決了使用gson.fromJson :) – ofleaf

回答

0

下面是一些解決此問題的建議。

  1. 不要直接使用字符串操作,直到真正需要它們時,可以通過使用JSON庫來解析JSON數據來避免拆分。您編寫的代碼越多,引入的bug越多,需要的維護越多。
  2. 使用對象建模。在HashMap中使用它會更具可讀性。通過定義peroperties pts,pts_itv,ptstime,ptstime_itv來創建對象模型。然後選擇您的鍵和值。定義equals和hashcode。然後用你自己的方式檢查對象是否相等,或使用equals。
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