Mysql排名，升序或降序

Question

我有一個查詢下面，使用排名方法基於points。問題是，如果我按順序排列，排名仍然顯示1,2,3,4等等，而不是4,3,2,1（或者如果只想獲得一個人排名（其中用戶名= name1），結果是回1，而不是他們的實際排名基於points）。我的代碼如下：

SELECT username, @n := @n + 1 ranking, `1st places`, `2nd places`, `3rd places`, `avg`, `1st places` + `2nd places` + `3rd places` AS `points` 
FROM (SELECT username, 
SUM(CASE WHEN rating = 1 THEN 10 ELSE 0 END) `1st places`, 
SUM(CASE WHEN rating = 2 THEN 5 ELSE 0 END) `2nd places`, 
SUM(CASE WHEN rating = 3 THEN 3 ELSE 0 END) `3rd places`, 
format(avg(rating),0) `avg` 

FROM contest_entries 
GROUP BY username 

) q, (SELECT @n := 0) n 
ORDER BY `points` desc 

所以我想要的東西，是能夠通過points仍然排名，但是如果我想通過ASC排名會去反... 4，3，2訂購，這可能嗎？

編輯*這是我使用上述代碼時的樣子。

username ranking 1st places 2nd places 3rd places avg points 
name3   1  10    5   0  1 15 
name1   2  10    0   0  1 10 
name2   3  0    0   0  6  0 

然而，當爲了通過點遞增，這是結果：

username ranking 1st places 2nd places 3rd places avg points 
name2   1  0    0   0  6 0 
name1   2  10    0   0  1 10 
name3   3  10    5   0  1 15 

的點是在倒車時，但排名保持不變。

Answer 1

select * from 
(SELECT username, @n := @n - 1 ranking, `1st places`, `2nd places`, `3rd places`, `avg`, `1st places` + `2nd places` + `3rd places` AS `points` 
FROM (SELECT username, 
SUM(CASE WHEN rating = 1 THEN 10 ELSE 0 END) `1st places`, 
SUM(CASE WHEN rating = 2 THEN 5 ELSE 0 END) `2nd places`, 
SUM(CASE WHEN rating = 3 THEN 3 ELSE 0 END) `3rd places`, 
format(avg(rating),0) `avg` 

FROM contest_entries 
GROUP BY username 

) q, (SELECT @n := count(distinct username)+1 from contest_entries) n 
ORDER BY `points` asc) resultset 
order by ranking asc; 

fiddle

如果你需要添加條件：

select * from 
(SELECT username, @n := @n - 1 ranking, `1st places`, `2nd places`, `3rd places`, `avg`, `1st places` + `2nd places` + `3rd places` AS `points` 
FROM (SELECT username, 
SUM(CASE WHEN rating = 1 THEN 10 ELSE 0 END) `1st places`, 
SUM(CASE WHEN rating = 2 THEN 5 ELSE 0 END) `2nd places`, 
SUM(CASE WHEN rating = 3 THEN 3 ELSE 0 END) `3rd places`, 
format(avg(rating),0) `avg` 

FROM contest_entries 
GROUP BY username 

) q, (SELECT @n := count(distinct username)+1 from contest_entries) 
n 
ORDER BY `points` asc) resultset where username = 'name1' 
order by ranking asc; 

fiddle