Django ajax HttpResponse json錯誤意外的令牌d

Question

我想要做一個Django ajax HttpResponse json使用medium-editor。

view.py

def test(request, union_id): 
if request.is_ajax(): 
    t = Union.objects.get(id=union_id) 
    message = json.loads(request.body) 
    t.description = message['description']['value'] 
    t.save() 
    return HttpResponse(message, mimetype="application/json") 
else: 
    message = "Not Ajax" 
    return HttpResponse(message) 

jQuery的（更新）

function getCookie(name) { 
     var cookieValue = null; 
     if (document.cookie && document.cookie != '') { 
      var cookies = document.cookie.split(';'); 
      for (var i = 0; i < cookies.length; i++) { 
       var cookie = jQuery.trim(cookies[i]); 
       // Does this cookie string begin with the name we want? 
       if (cookie.substring(0, name.length + 1) == (name + '=')) { 
        cookieValue = decodeURIComponent(cookie.substring(name.length + 1)); 
        break; 
       } 
      } 
     } 
     return cookieValue; 
    } 
    var csrftoken = getCookie('csrftoken'); 

    function csrfSafeMethod(method) { 
     // these HTTP methods do not require CSRF protection 
     return (/^(GET|HEAD|OPTIONS|TRACE)$/.test(method)); 
    } 
    $.ajaxSetup({ 
     crossDomain: false, // obviates need for sameOrigin test 
     beforeSend: function(xhr, settings) { 
      if (!csrfSafeMethod(settings.type)) { 
       xhr.setRequestHeader("X-CSRFToken", csrftoken); 
      } 
     } 
    }); 

    $('#savecontentObj').click(function() { 
     var contentObj = editor.serialize(); 
     obj = JSON.stringify(contentObj); 
     $.ajax({ 
      url:"update", 
      type: "POST", 
      data: obj, 
      dataType: "json", 
      contentType: "application/json", 
      success:function(response){ 
       console.log('success'); 
      }, 
      complete:function(){ 
       console.log('complete'); 
      }, 
      error:function (xhr, textStatus, thrownError){ 
       console.log(thrownError); 
       console.log(obj); 
      } 
     }); 
    }); 

的console.log

SyntaxError {stack: (...), message: "Unexpected token d"} 
{"description":{"value":"<p>dddddd</p>"}} 
complete 

這是節約 '說明' 到數據庫，但我不會取得成功在httpresponse中，你可以在console.log中看到。

非常感謝！確保您的AJAX的網址是不是按你的觀點和方法也CSRF令牌必須連載值存在

更新

url.py

url(r'^(?P<union_id>\d+)/update$', views.test), 

Answer 1

def test(request, union_id): 
if request.is_ajax(): 
    t = Union.objects.get(id=union_id) 
    t.description = request.POST.get('description',None) 
    t.save() 
    HttpResponse(json.dumps(dict(status='updated')), mimetype="application/json") 
else: 
    message = "Not Ajax" 
    HttpResponse(json.dumps(dict(status="Not Ajax")), mimetype="application/json") 

$('#savecontentObj').click(function() { 
     var contentObj = editor.serialize(); 
     $.ajax({ 
      url:"update", 
      type: "POST", 
      data: contentObj, 
      dataType: "json", 
      success:function(data){ 
       console.log(data.success); 
      }, 
      complete:function(){ 
       console.log('complete'); 
      }, 
      error:function (xhr, textStatus, thrownError){ 
       console.log(thrownError); 
       console.log(obj); 
      } 
     }); 
    }); 

製作。