如何列出rhythmbox插件中的所有藝術家

Question

我想從rhythmbox python插件中列出rhythmbox數據庫中的所有藝術家。我找到的唯一解決方案是讓用戶界面選擇所有藝術家和所有歌曲，遍歷每首歌曲並將該歌曲的藝術家名稱添加到一個集合中。

這個問題是（除了事實上它是痛苦的低效率），我不想僅僅因爲我想要數據庫中所有藝術家的列表而改變選定的藝術家。我之前嘗試保存選定的藝術家，以便在完成後恢復它，但由於UI需要一些時間才能更新新信息和更多信息（即更多的歌曲數據庫），需要的時間就越多。

的代碼可以與獲取 混帳克隆git@github.com：sameltvom/dblister.git

下面是代碼：

import rb 
import rhythmdb 
import gtk 

class DblisterPlugin (rb.Plugin): 
    def __init__(self): 
     rb.Plugin.__init__(self) 
    def activate(self, shell): 
     self.shell = shell 
     print '##### dblister #####' 

     # choose all artists, this will choose all albums and songs as well 

     # get the lock for rhythmbox ui 
     gtk.gdk.threads_enter() 
     for p in self.shell.props.library_source.get_property_views(): 
      if p.props.prop == rhythmdb.PROP_ARTIST: 
       p.set_selection([""]) 
       break 
     gtk.gdk.threads_leave() 

     ##################### Print all artists in database ###################### 

     # loop through all songs currently selected (i.e. all songs since we did p.set_selection([""]) above 
     # for each song, try to add the artist name to the 'artists' set 
     artists = set() # unique keys, no duplicates 
     for row in self.shell.props.selected_source.props.query_model: 
      entry = row[0] 
      artist = self.shell.props.db.entry_get(entry, rhythmdb.PROP_ARTIST) 
      artists.add(artist) 

     print '--- artists ---' 
     for artist in artists: 
      print artist 


     ##################### Print all songs in database ###################### 

     print '--- songs ---' 
     # loop through all songs currently selected (i.e. all songs since we did p.set_selection([""]) above 
     # for each song, print artist name and title 
     for row in self.shell.props.selected_source.props.query_model: 
      entry = row[0] 
      artist = self.shell.props.db.entry_get(entry, rhythmdb.PROP_ARTIST) 
      song = self.shell.props.db.entry_get(entry, rhythmdb.PROP_TITLE) 
      print artist + ' - ' + song 

    def deactivate(self, shell): 
     del self.shell 
     print 'Bye world' 

我想這樣做的原因是因爲我正在開發一個telnet界面到rhythmbox，https://github.com/sameltvom/rhythmcurse。

樂於輸入！

親切的問候， 塞繆爾

Answer 1

我找到了！如果我想列出所有條目，而不管用戶界面中選擇了什麼，那麼我應該使用它的屬性base_query_model。

代碼現在看起來像：

import rb 
import rhythmdb 
import gtk 

class DblisterPlugin (rb.Plugin): 
    def __init__(self): 
     rb.Plugin.__init__(self) 
    def activate(self, shell): 
     self.shell = shell 
     print '##### dblister #####' 


     #################### Print all artists in the library #################### 
     artists = set() # unique keys, no duplicates 
     for row in self.shell.props.library_source.props.base_query_model: 
      entry = row[0] 
      artist = self.shell.props.db.entry_get(entry, rhythmdb.PROP_ARTIST) 
      artists.add(artist) 

     print '--- artists using library_source---' 
     for artist in artists: 
      print artist 

     del artists 


     ##################### Print all artists in database ###################### 

     artists = set() # unique keys, no duplicates 
     for row in self.shell.props.selected_source.props.base_query_model: 
      entry = row[0] 
      artist = self.shell.props.db.entry_get(entry, rhythmdb.PROP_ARTIST) 
      artists.add(artist) 

     print '--- artists ---' 
     for artist in artists: 
      print artist 


     ##################### Print all songs in database ###################### 

     print '--- songs ---' 
     for row in self.shell.props.selected_source.props.base_query_model: 
      entry = row[0] 
      artist = self.shell.props.db.entry_get(entry, rhythmdb.PROP_ARTIST) 
      song = self.shell.props.db.entry_get(entry, rhythmdb.PROP_TITLE) 
      print artist + ' - ' + song 

    def deactivate(self, shell): 
     del self.shell 
     print 'Bye world' 

我也發現了另一個好處，以及。如果我使用elf.shell.props.library_source.props.base_query_model而不是self.shell.props.selected_source.props.base_query_model，即使我可能已將視圖更改爲例如Last.FM或Radio在左側窗格中。

但是，我仍然必須循環播放所有歌曲才能找到所有藝術家。但主要問題沒有了。