使用XML的VB.NET服務器協議違規「Section = ResponseStatusLine」

我試圖發送一個XML片段到我的本地主機服務器。我已經能夠成功連接和（我認爲）成功發送片段。但是，當我運行我的程序時，我得到一個未處理的WebException。異常詳細信息全文如下：使用XML的VB.NET服務器協議違規「Section = ResponseStatusLine」

System.Net.WebException was unhandled 
Message=The server committed a protocol violation. Section=ResponseStatusLine 
Source=System 
StackTrace: 
    at System.Net.HttpWebRequest.GetResponse() 
    at Automation_Algorithm.AutomationForm.cmdStart_Click(Object sender, EventArgs e) in C:\Users\ConzM\documents\visual studio 2010\Projects\Automation Algorithm\Automation Algorithm\AutomationForm.vb:line 29 
    at System.Windows.Forms.Control.OnClick(EventArgs e) 
    at System.Windows.Forms.Button.OnClick(EventArgs e) 
    at System.Windows.Forms.Button.OnMouseUp(MouseEventArgs mevent) 
    at System.Windows.Forms.Control.WmMouseUp(Message& m, MouseButtons button, Int32 clicks) 
    at System.Windows.Forms.Control.WndProc(Message& m) 
    at System.Windows.Forms.ButtonBase.WndProc(Message& m) 
    at System.Windows.Forms.Button.WndProc(Message& m) 
    at System.Windows.Forms.Control.ControlNativeWindow.OnMessage(Message& m) 
    at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m) 
    at System.Windows.Forms.NativeWindow.DebuggableCallback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam) 
    at System.Windows.Forms.UnsafeNativeMethods.DispatchMessageW(MSG& msg) 
    at System.Windows.Forms.Application.ComponentManager.System.Windows.Forms.UnsafeNativeMethods.IMsoComponentManager.FPushMessageLoop(IntPtr dwComponentID, Int32 reason, Int32 pvLoopData) 
    at System.Windows.Forms.Application.ThreadContext.RunMessageLoopInner(Int32 reason, ApplicationContext context) 
    at System.Windows.Forms.Application.ThreadContext.RunMessageLoop(Int32 reason, ApplicationContext context) 
    at Microsoft.VisualBasic.ApplicationServices.WindowsFormsApplicationBase.OnRun() 
    at Microsoft.VisualBasic.ApplicationServices.WindowsFormsApplicationBase.DoApplicationModel() 
    at Microsoft.VisualBasic.ApplicationServices.WindowsFormsApplicationBase.Run(String[] commandLine) 
    at Automation_Algorithm.My.MyApplication.Main(String[] Args) in 17d14f5c-a337-4978-8281-53493378c1071.vb:line 81

我的代碼（在第11場首發）：

Private Sub cmdStart_Click(sender As System.Object, e As System.EventArgs) Handles cmdStart.Click 
    Dim requestNF As WebRequest = WebRequest.Create("http://127.0.0.1:4096") 
    requestNF.Method = "POST" 
    Dim datastring As String 
    Dim getdata = 
     <?xml version='1.0' encoding='ISO-8859-1'?> 
     <MLCommandSet> 
      <info/> 
     </MLCommandSet>                  '/ 
    datastring = "<?xml version='1.0' encoding='ISO-8859-1'?>" & vbNewLine & getdata.ToString() 
    Dim byteArray As Byte() = Encoding.UTF8.GetBytes(datastring) 
    requestNF.ContentLength = byteArray.Length 
    requestNF.ContentType = "text/xml" 
    Dim dataStream As Stream = requestNF.GetRequestStream() 
    dataStream.Write(byteArray, 0, byteArray.Length) 
    txtXMLOutFF.AppendText(getdata.ToString & vbNewLine) 
    dataStream.Close() 

    Dim responseNF As Object = requestNF.GetResponse.GetResponseStream '<---breaks here' 
    Console.WriteLine(CType(responseNF, HttpWebResponse).StatusDescription.ToString) 
    txtXMLInFF.Text = CType(responseNF, HttpWebResponse).StatusDescription.ToString 
    dataStream = responseNF.GetResponseStream 
    Dim readerNF As New StreamReader(dataStream) 
    Dim responseFromServerNF As String = readerNF.ReadToEnd 
    Console.WriteLine(responseFromServerNF) 
    txtXMLInFF.AppendText(responseFromServerNF.ToString & vbNewLine) 
    readerNF.Close() 
    dataStream.Close() 
    responseNF.Close() 
End Sub

有人能提供一些線索這對我來說？

來源

2012-06-26 Matt

儘管我還沒有達到與應用程序通信的預期目標，但我確實發現問題是通信是通過原始TCP/IP消息，而不是像我所假設的XML或HTTP請求。所以，我想出了一個解決疑難清單運行時，你得到的「服務器違反協議：條：ResponseStatusLine」錯誤：

下面的代碼添加到您的app.config文件：（它允許不正確頭部可以通過）

<system.net> 
    <settings> 
     <httpWebRequest useUnsafeHeaderParsing = "true"/> 
    </settings> 
</system.net>

如果在清理和重建後不起作用，那麼您連接的服務器可能不會發送WebRequest數據。爲了測試這個，我使用了一個Telnet客戶端。
要使用Telnet測試數據，請下載並打開Telnet客戶端（Windows，我建議PuTTYtel，Unix和其他人通常可以啓動他們的終端/命令提示符並鍵入telnet來激活）。

a）輸入您嘗試連接的服務器和相應字段中的端口號（Windows）或在終端中鍵入telnet -o servername:portnumber，然後按Enter鍵。（Unix/Linux風格）

b）當窗口出現時，嘗試輸入原始查詢，仔細記錄任何空白或換行規範。在我的情況下，我鍵入：
```
<?xml version='1.0' encoding='ISO-8859-1'?> 
<MLCommandSet> 
    <info/> 
</MLCommandSet> 
```
並按下回車鍵。當我這樣做時，我立即看到了我正在尋找的應用程序的輸出。：D
但是，如果這不起作用，請在其他地方尋找解決方案，因爲我可以幫您解決問題。

希望這有助於！

來源

2012-06-27 09:11:26 Matt

使用XML的VB.NET服務器協議違規「Section = ResponseStatusLine」

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