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基本上，我試圖創建一個表獲取用戶輸入並檢查答案是否正確。檢查輸入按鈕
我希望它根據用戶的答案更改第4列以更正或不正確。
這裏是我的嘗試：
<form name="input" action="javascript:void(0);" method="get">
<table id="compsci-table" style = "margin: auto;">
<tr>
<th>Microsoft Office</th>
<th>Example</th>
<th>Extension</th>
<th>Feedback</th>
</tr>
<tr>
<td>Word Processing</td>
<td>Word</td>
<td>
<form id="form1" method="" action="" onsubmit="return validateAns(wpExtension)">
<input type="text" name="wpExtension">
<input type="submit" name="b1" value="Check" class="submitbutton aligncenter"/>
</form>
<script>
function validateAns(Ans) {
if(Ans == "docx")
alert("Correct!");
$("#formA").submit(function() {
$("#reveal-space1").text("Correct").show();
return true;
});
else
alert("Incorrect.");
$("#formA").submit(function() {
$("#reveal-space1").text("Incorrect").show();
return true;
});
</script>
</td>
<td>
<form id="formA" action="javascript:void(0);">
<div id="reveal-space1">
</div>
</form>
</td>
</tr>
<tr>
<td>Spreadsheet</td>
<td>
<form id="form2" method="" action="" onsubmit="return validateAns(ssExample)">
<input type="text" name="ssExample">
<input type="submit" name="b1" value="Check" class="submitbutton aligncenter"/>
</form>
<script>
function validateAns(Ans) {
if(Ans == "Excel")
alert("Correct!");
$("#formA").submit(function() {
$("#reveal-space2").text("Correct").show();
return true;
});
else
alert("Incorrect.");
$("#formA").submit(function() {
$("#reveal-space2").text("Incorrect").show();
return true;
});
</script>
</td>
<td>xlsx</td>
<td>
<form id="formB" action="javascript:void(0);">
<div id="reveal-space2">
</div>
</form>
</td>
</tr>
在正確的方向任何指導將不勝感激。