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我試圖從url中獲取json數據。我的數據如下:無法從url中獲取json數據android
[{"Food1":"Fried Chicken","Food2":"Spagetti","Food3":"Watermelon"}]
我已經搜索了它,幾乎嘗試了我可以找到的每個代碼。但他們沒有爲我工作。 當我手動給出一個json數據我可以很容易地解析它,真正的問題是通過使用HttpClient或Httpurlconnection從URL獲取數據。我也嘗試過使用AsyncTask,但是我無法正確地做到這一點。我該怎麼辦 ?
的logcat:https://dl.dropboxusercontent.com/u/108584907/logcat.txt
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
import android.widget.TextView;
public class yemekhane extends Activity {
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.yemekhane);
TextView tv = (TextView) findViewById(R.id.TextView01);
JSONArray jArray = null;
String result = "";
StringBuilder sb = null;
InputStream is = null;
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
try{
HttpClient httpclient = new DefaultHttpClient();
//Why to use 10.0.2.2
HttpPost httppost = new HttpPost("http://example.com");
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
HttpEntity entity = response.getEntity();
is = entity.getContent();
}catch(Exception e){
Log.e("log_tag", "Error in http connection"+e.toString());
}
//convert response to string
try{
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
sb = new StringBuilder();
sb.append(reader.readLine() + "\n");
String line="0";
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result=sb.toString();
}catch(Exception e){
Log.e("log_tag", "Error converting result "+e.toString());
}
String name = "";
try {
jArray = new JSONArray(result);
JSONObject json_data=null;
for(int i=0;i<jArray.length();i++){
json_data = jArray.getJSONObject(i);
name=json_data.getString("Food1");
}
} catch (JSONException e1) {
// TODO Auto-generated catch block
e1.printStackTrace();
}
tv.setText("test " + name);
}
}`
慈祥發佈logcat的PLZ – KOTIOS
發表關於你做了什麼一些代碼。只是在這裏發佈JSON不會幫助。 – rockstar
你確定你得到的迴應是你的想法嗎?在解析之前嘗試打印它。 – Steelight