如何從返回JSON從Web服務訪問數據的JavaScript或jQuery的

嗨，我有它返回的web服務 Web服務的結構就是這樣一個返回JSON數據：如何從返回JSON從Web服務訪問數據的JavaScript或jQuery的

jsonp1332655154667({"products": [{"uid": "37", 
"samsid": "hjk", 
"name": "Science%20Essentials%2010%20AC%20edn", 
"shortname": "scienceessentials10", 
"description": "Science%20Essentials%2010%20ACE%20is%20the%20fourth%20in%20a%20series%20of%20four%20books%20designed%20for%20the%20National%20Curriculum.%20", 
"generated": "3/25/2012%205:59:19%20AM", 
"Description": "Science%20Essentials%2010%20ACE%20is%20the%20fourth%20in%20a%20series%20of%20four%20books%20designed%20for%20the%20National%20Curriculum.%20", 
"PublishingCompany": "Macmillan%20Australia", 
"Service": "OneStopScience", 
"Service": "OneStopDigital", 
"Icon": "http://curriculumplatform.s3.amazonaws.com/prod/icons/brain48.png", 
"Country": "Australia", 
"Shortname": "scienceessentials10", 
"MarketingSite": "http%3a%2f%2fwww.macmillan.com.au%2fsecondary%2fonix%2fall%2f6F597241EFC0E43DCA257791001CAFC0%3fopen%26div%3dSecondary%26cat%3dScience%253EAustralian%252BCurriculum%26template%3ddomSecondary%26ed%3dsite%2fseced31.nsf", 
"Skin": "OneStopScience%20Green"}, 
"tag":"s_science"' 
"tag":"s_maths"' 
"tag":"s_arts", 
{"uid": "5",}]})

我有三個「標籤」元素。但是當我們訪問products.tag時，它總是給出最後一個元素，如：s_arts。有什麼方法可以找出所有的元素，例如：s_science，s_maths，s_arts。請幫忙。

來源

2012-03-25 vipin katiyar

嘗試'console.log（products.tag）'並告訴我們會發生什麼 – Joseph 2012-03-25 06:12:15

是不是無效的JSON？ – bernie 2012-03-25 06:14:09

它給出標籤：s_arts標籤的最後一個元素。 – 2012-03-25 06:14:57

如果你在同一個對象中有多個鍵，你將會得到未定義的行爲。只有一個會被保留下來，因爲對沒有排序，所以你不能保證你會得到哪一個。

簡而言之：web服務正在返回錯誤數據。如果多個標籤預計，該服務應在標籤屬性返回值的數組：

... 
"tag":["s_science", "s_maths", "s_arts"], 
...

來源

2012-03-25 06:15:14 Hamish

它是無效的JSON，你的標籤應該是：

..., 
"tag": ["s_science", "s_maths", "s_arts" ], 
...

然後product.tag將是一個數組，你可以訪問成功

問候

來源

2012-03-25 06:16:52 grifos

我不確定它本身是無效的，但它只能拿一個，我發現它總是需要定義最後一個。 – Tuan 2012-03-25 06:31:01

您需要發送標籤作爲數組：

jsonp1332655154667({"products": [{"uid": "37", 
"samsid": "hjk", 
"name": "Science%20Essentials%2010%20AC%20edn", 
"shortname": "scienceessentials10", 
"description": "Science%20Essentials%2010%20ACE%20is%20the%20fourth%20in%20a%20series%20of%20four%20books%20designed%20for%20the%20National%20Curriculum.%20", 
"generated": "3/25/2012%205:59:19%20AM", 
"Description": "Science%20Essentials%2010%20ACE%20is%20the%20fourth%20in%20a%20series%20of%20four%20books%20designed%20for%20the%20National%20Curriculum.%20", 
"PublishingCompany": "Macmillan%20Australia", 
"Service": "OneStopScience", 
"Service": "OneStopDigital", 
"Icon": "http://curriculumplatform.s3.amazonaws.com/prod/icons/brain48.png", 
"Country": "Australia", 
"Shortname": "scienceessentials10", 
"MarketingSite": "http%3a%2f%2fwww.macmillan.com.au%2fsecondary%2fonix%2fall%2f6F597241EFC0E43DCA257791001CAFC0%3fopen%26div%3dSecondary%26cat%3dScience%253EAustralian%252BCurriculum%26template%3ddomSecondary%26ed%3dsite%2fseced31.nsf", 
"Skin": "OneStopScience%20Green"}, 
"tags": [ 
    "s_science"' 
    "s_maths"' 
    "s_arts" 
], 
{"uid": "5",}]})

然後您將它們引用爲data.tags[0], data.tags[1], data.tags[2]。

來源

2012-03-25 06:28:52 Tuan

如果你的反應是這種格式

YourResponse = { 
    "products" : [ 
        {"uid" :"5", ......., "whtever":"someval"}, 
        {"uid" :"6", ......., "whtever":"someval1"} 
       ] 

};

您可以使用此

$(YourResponse).each(
function(objName, objValue) { 
    console.log(objName); // wil get object name like uid, whtever 
    console.log(objValue); // wil get object's value 

});

所以要得到標籤，你將不得不採取團的建議;發送他們在陣列

來源

2012-03-25 06:32:44

如何從返回JSON從Web服務訪問數據的JavaScript或jQuery的

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