在android中使用json

Question

我正在開發一個帶有銷售和採購管理的項目詳細方法的android應用程序。

對於我使用的登錄和其他屏幕應用..

我的項目已經在SQLite數據庫正常運行，我怎麼可以把它作爲集中使用JSON？

Answer 1

您可以使用JSON與PHP和MySQL的集中化應用..

請參見下面的教程爲登錄活動..

login

和其他數據庫活動，如，創建，插入，提取，更新和刪除服務器端數據庫上的數據，請按照本教程進行：

PHP & MYSQL

這裏最重要的是，你需要爲你的應用程序的服務器端數據庫..

而下面的java文件是JSON活動更重要，..

JSONParser.java 
package com.example.androidhive; 

import java.io.BufferedReader; 
import java.io.IOException; 
import java.io.InputStream; 
import java.io.InputStreamReader; 
import java.io.UnsupportedEncodingException; 
import java.util.List; 
import org.apache.http.HttpEntity; 
import org.apache.http.HttpResponse; 
import org.apache.http.NameValuePair; 
import org.apache.http.client.ClientProtocolException; 
import org.apache.http.client.entity.UrlEncodedFormEntity; 
import org.apache.http.client.methods.HttpGet; 
import org.apache.http.client.methods.HttpPost; 
import org.apache.http.client.utils.URLEncodedUtils; 
import org.apache.http.impl.client.DefaultHttpClient; 
import org.json.JSONException; 
import org.json.JSONObject; 
import android.util.Log; 
public class JSONParser { 
static InputStream is = null; 
static JSONObject jObj = null; 
static String json = ""; 
// constructor 
public JSONParser() { 
} 
// function get json from url 
// by making HTTP POST or GET method 
public JSONObject makeHttpRequest(String url, String method, 
     List<NameValuePair> params) { 
    // Making HTTP request 
    try { 
     // check for request method 
     if(method == "POST"){ 
      // request method is POST 
      // defaultHttpClient 
      DefaultHttpClient httpClient = new DefaultHttpClient(); 
      HttpPost httpPost = new HttpPost(url); 
      httpPost.setEntity(new UrlEncodedFormEntity(params)); 
      HttpResponse httpResponse = httpClient.execute(httpPost); 
      HttpEntity httpEntity = httpResponse.getEntity(); 
      is = httpEntity.getContent(); 
     }else if(method == "GET"){ 
      // request method is GET 
      DefaultHttpClient httpClient = new DefaultHttpClient(); 
      String paramString = URLEncodedUtils.format(params, "utf-8"); 
      url += "?" + paramString; 
      HttpGet httpGet = new HttpGet(url); 
      HttpResponse httpResponse = httpClient.execute(httpGet); 
      HttpEntity httpEntity = httpResponse.getEntity(); 
      is = httpEntity.getContent(); 
     }   
    } catch (UnsupportedEncodingException e) { 
     e.printStackTrace(); 
    } catch (ClientProtocolException e) { 
     e.printStackTrace(); 
    } catch (IOException e) { 
     e.printStackTrace(); 
    } 
    try { 
     BufferedReader reader = new BufferedReader(new InputStreamReader(
       is, "iso-8859-1"), 8); 
     StringBuilder sb = new StringBuilder(); 
     String line = null; 
     while ((line = reader.readLine()) != null) { 
      sb.append(line + "\n"); 
     } 
     is.close(); 
     json = sb.toString(); 
    } catch (Exception e) { 
     Log.e("Buffer Error", "Error converting result " + e.toString()); 
    } 
    // try parse the string to a JSON object 
    try { 
     jObj = new JSONObject(json); 
    } catch (JSONException e) { 
     Log.e("JSON Parser", "Error parsing data " + e.toString()); 
    } 
    // return JSON String 
    return jObj; 
} 
} 

Answer 2

http://www.androidhive.info/2012/01/android-json-parsing-tutorial/

參考上面鏈接Jsonparsing教程。基本上你會需要從url返回json對象的例子中的JSONParser.java。

鏈接還包括可下載的代碼。但請確保使用AsyncTask來執行所有基於網絡的任務。