非常基本的Spring websocket返回404

Question

我正在學習使用Spring WebSockets，但我無法獲得一個非常基本的示例來工作，我收到一個404錯誤。 我用http://docs.spring.io/spring/docs/current/spring-framework-reference/html/websocket.html作爲參考。

的WebSocketConfig：

@Configuration 
@EnableWebSocket 
public class WebSocketConfig implements WebSocketConfigurer { 
    private Logger logger = Logger.getLogger(WebSocketConfig.class); 

    @Override 
    public void registerWebSocketHandlers(WebSocketHandlerRegistry registry) { 
     logger.debug("Registering websocket handler"); 
     registry.addHandler(gameWebSocketHandler(), "/StreamGame/ws/play"); 
    } 

    @Bean 
    public WebSocketHandler gameWebSocketHandler() { 
     return new GameWebSocketHandler(); 
    } 
} 

的WebSocketHandler：

public class GameWebSocketHandler extends TextWebSocketHandler { 
    final static Logger logger = Logger.getLogger(GameWebSocketHandler.class); 

    public GameWebSocketHandler() { 
     logger.debug("Constructor handler"); 
    } 

    @Override 
    public void handleTransportError(WebSocketSession session, Throwable exception) throws Exception { 
     super.handleTransportError(session, exception); 
     logger.error("Transport error: " + exception.getMessage()); 
    } 

    @Override 
    public void handleTextMessage(WebSocketSession session, TextMessage message) throws Exception { 
     logger.info("Handle message received: " + message.getPayload()); 
     //session.sendMessage(new TextMessage("Here is your answer")); 
    } 

    @Override 
    public void afterConnectionEstablished(WebSocketSession session) throws Exception { 
     super.afterConnectionEstablished(session); 
     logger.info("Connection established!"); 
    } 
} 

除非我弄錯，即使有這樣的我應該能夠通過WebSocket的從客戶端發送消息到服務器。以下：

sock = new WebSocket('ws://localhost:8080/StreamGame/ws/play'); 

我在連接時收到以下錯誤：

WebSocket的握手期間錯誤：意外響應代碼：404WrappedWebSocket @ VM84：35（匿名功能）@（指數）：11J @ jquery的-3.1.1.min.js：2K @ jQuery的3.1.1.min的.js：2 （指數）：26錯誤未定義

Web.xml中包含以下內容：

<!-- Processes application requests --> 
    <context-param> 
     <param-name>contextConfigLocation</param-name> 
     <param-value>/WEB-INF/application-context.xml</param-value> 
    </context-param> 

    <listener> 
     <listener-class> 
      org.springframework.web.context.ContextLoaderListener 
     </listener-class> 
    </listener> 
    <servlet> 
     <servlet-name>SpringMVCDispatcherServlet</servlet-name> 
     <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> 
     <init-param> 
      <param-name>contextConfigLocation</param-name> 
      <param-value>/WEB-INF/application-context.xml</param-value> 
     </init-param> 
     <load-on-startup>1</load-on-startup> 
    </servlet> 

    <!-- Mapping websocket to spring dispatcher servlet --> 
    <servlet-mapping> 
     <servlet-name>SpringMVCDispatcherServlet</servlet-name> 
     <url-pattern>/ws/*</url-pattern> 
    </servlet-mapping> 

我Spring應用程序上下文包含：

當連接的WebSocket我看到在服務器日誌如下：

>  2016-11-13 TRACE - 39804 - org.springframework.web.servlet.DispatcherServlet - 
> http-nio-8080-exec-2 - Bound request context to thread: 
> org.apache.catalina.connector.RequestFacade@df5f117 
>  2016-11-13 DEBUG - 39804 - org.springframework.web.servlet.DispatcherServlet - 
> http-nio-8080-exec-2 - DispatcherServlet with name 
> 'SpringMVCDispatcherServlet' processing GET request for 
> [/StreamGame/ws/play] 
>  2016-11-13 TRACE - 39804 - org.springframework.web.servlet.DispatcherServlet - 
> http-nio-8080-exec-2 - Testing handler map 
> [org.springframework.web.socket.server.support.WebSocketHandlerMapping@4e92ebf3] 
> in DispatcherServlet with name 'SpringMVCDispatcherServlet' 
>  2016-11-13 TRACE - 39804 - org.springframework.web.socket.server.support.WebSocketHandlerMapping 
> - http-nio-8080-exec-2 - No handler mapping found for [/play] 
>  2016-11-13 WARN - 39804 - org.springframework.web.servlet.PageNotFound - http-nio-8080-exec-2 - 
> No mapping found for HTTP request with URI [/StreamGame/ws/play] in 
> DispatcherServlet with name 'SpringMVCDispatcherServlet' 

Answer 1

的addHandler操作功能需要被映射到「/播放」，因此不包括根上下文（StreamGame）和調度映射（/ WS）。更改addHandler操作解決問題：

registry.addHandler(gameWebSocketHandler(), "/play"); 

打開時，如下連接WebSocket的：

sock = new WebSocket('ws://localhost:8080/StreamGame/ws/play'); 

Answer 2

看來你的WebSocket URL不正確。您註冊/播放作爲處理程序，但稱/StreamGame /播放

還要記住的是，WS連接異步創建的，所以你必須等待連接握手發送消息，像這樣前完成：

var ws = new WebSocket("ws://localhost:8080/play"); 
ws.onopen = function() { 
    ws.send('AHOIHOI'); 
} 
ws.onerror = function(error) { 
    // handle connection error 
}