循環直到（py）

Question

amount_of_names = int(input("Input amount of players: ")) 
names = [] 

for counter in range(amount_of_names): 
    name = str(input("Input players first name: ")) 
    names.append(name) 
#print (names) 
selected_name = str(input("Input your name: ")) 

while name in names: 
    import random 
    names = random.choice(names) 
    break 
print (names) 

我試圖用名稱與「你的名字」進行匹配，然後循環，直到名稱不匹配例如Bob：Sam（是）Sam：Sam（No） - 在此先感謝所有

Answer 1

製作一個list，然後將其添加到append。

AmountOfNames = int(input("Input amount of players: ")) 
Names = [] 

for counter in range (0, AmountOfNames): 
    RegisteredName = input("Input player {}'s first name: ".format(counter+1)) 
    Names.append(RegisteredName) 

print(Names) 

例子：

Input amount of players: 3 
Input player 1's first name: Simon 
Input player 2's first name: James 
Input player 3's first name: Jacob 
['Simon', 'James', 'Jacob'] 

或者你可以這樣做：

>>> names = input("Enter the first names of the players: ").split(", ") 
Enter the first names of the players: Simon, James, Jacob 
>>> names 
['Simon', 'James', 'Jacob'] 

利用上述方法，如果他們不與他們逗號和空格每次分開，它會毛刺，所以要非常小心。

Answer 2

試試這個：現在

amount_of_names = int(input("Input amount of players: ")) 
names = [] 

for counter in range(amount_of_names): 
    name = str(input("Input players first names: ")) 
    names.append(name) 

print names 

，names列表包含amount_of_names名

Answer 3

做一個空數組圈外的一面。例如。 NameList = []然後，在循環中，對於每次迭代，將名稱添加到使用NameList.append（//名稱）的列表中