-1
下面是我的觀點之一,我得到我的網址所期望的結果,即Django的蟒蛇 - 改變蛞蝓不是重定向到404頁
本地主機/員工/ 0001/reportees
但是,當我改變slu of我的網址它不會重定向到404頁面insted它會顯示相同的結果,上面和下面的url給我相同的結果。當slu is改變時,如何讓頁面轉到404。注:兩者顯示同樣的結果達指URL對生成的結果沒有任何影響
本地主機/員工/技術/ reportees
class EmployeeReporteeView(LoginRequiredMixin, ListView):
model = employee
template_name = "employee_reportees.html"
slug_field = "slug"
def get_context_data(self, **kwargs):
self.base_qs = super(EmployeeReporteeView, self).get_queryset()
context = super(EmployeeReporteeView, self).get_context_data(**kwargs)
context['primary_list'] = self.base_qs.filter(primary=self.request.user.employee.empid)
context['secondary_list'] = self.base_qs.filter(secondary=self.request.user.employee.empid)
return context
只給一個想法,我有這樣的下面視圖詳細視圖在當我改當員工0001本頁面登錄其重定向到404 蛞蝓顯示了他的個人資料 本地主機/員工/ 0001 其中爲localhost /員工/技術會重定向到404,因爲他看不到其他員工詳細
class EmployeeDetailView(LoginRequiredMixin, DetailView):
model = employee
template_name = "employee_detail.html"
context_object_name = "employee_detail"
def get_queryset(self):
base_qs = super(EmployeeDetailView, self).get_queryset()
return base_qs.filter(email=self.request.user)
# urls.py
url(r"^(?P<slug>[\w-]+)/$", EmployeeDetailView.as_view(), name="employee_detail"),
url(r"^(?P<slug>[\w-]+)/reportees/$", EmployeeReporteeView.as_view(), name="employee_reportees"),
我不知道爲什麼這個問題得到否定的投票:(這是我問過錯的東西嗎?或者是否有更少的細節解釋問題? – just10minutes