如何刪除mysqli的埃羅

Question

即時得到這個錯誤 警告：mysqli_error（）期望的是1個參數，0 給我不明白爲什麼它給我的代碼是吹在這裏

<?php 
// display add blog script and insert query 
} else { 

if(isset($_POST['submit'])) 
{ 
$heading = htmlentities($_POST['heading']); 
$description = htmlentities($_POST['description']); 
$heading = str_replace(' ', '-', $heading); 
$cat_name = $_POST['blog_cat']; 
$fileToUpload = basename($_FILES['fileToUpload']['name']); 
$target_dir = "uploads/blog/"; 
$target_file = $target_dir.$fileToUpload; 
$db_insert_image = "company_profile/".$target_file; 
$date = date("y-m-d"); 
$query = mysqli_query($conn, "INSERT INTO blog SET heading='$heading', 
description='$description', blog_cat='$cat_name', image='$db_insert_image', 
author='$ename', status='1', created_date='$date'"); 

if ($query) { 
if(move_uploaded_file($_FILES["fileToUpload"]["tmp_name"],$target_file)) { 
    echo "<script>alert('Image uploaded.')</script>"; 
    header("location:manageBlog.php"); 
    exit(); 
} else { 
    echo "<script>alert('There was a problem uploading image.')</script>"; 
} 
} else { 
echo mysqli_error(); 
echo "<script>alert('There was a problem with query, please try again.') 
</script>"; 
} 

}

？>

Answer 1

用這個替換你的$ query語句並刪除mysqli_error（）行。 如果有任何錯誤，它將自動運行mysqli_error（）。

$query = mysqli_query($conn, "INSERT INTO blog SET heading='$heading', 
description='$description', blog_cat='$cat_name', image='$db_insert_image', 
author='$ename', status='1', created_date='$date'") 
or die(mysqli_error($conn)); 

Answer 2

您應該更改mysqli_error（）;至mysqli_error（$ conn）;

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