是的,這是有效的。除了訪問jsp或jsf頁面外,您還可以訪問Servlet。所以創建一個新的servlet。例如:
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* Servlet implementation class TestServlet
*/
public class TestServlet extends HttpServlet {
private static final long serialVersionUID = 1L;
public static void yourMethod() {
// do something useful
}
/**
* @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
*/
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
yourMethod();
}
/**
* @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
*/
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
}
}
然後在web.xml文件中創建一個新條目,以便將Servlet映射到/。
<servlet>
<display-name>TestServlet</display-name>
<servlet-name>TestServlet</servlet-name>
<servlet-class>your.packages.TestServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>TestServlet</servlet-name>
<url-pattern>/TestServlet</url-pattern>
</servlet-mapping>
在此之後,您應該可以調用localhost:8080/TestServlet
然後調用您的方法。
看到這個[相關問題](http://stackoverflow.com/q/5522702/620338) – 2012-04-23 07:25:24
@MattHandy你能給更多關於AjaxBehaviorEvent的信息?我必須重新加載我的頁面幾種類型才能看到應該顯示的所有內容 – sameer 2012-04-23 08:16:17
您不需要此處。也許你需要使用屬性'update =「@ all」'更新你的ajax調用的整個頁面。 – 2012-04-23 08:24:06