MySQL的選擇1000增量數

Question

是否有可能選擇增加的數字，如：

num 
1000 
1001 
1002 
1003 
1004 
... 
1999 

我已經試過：

set @i=999; 
select @i:=@i+1 as num 
limit 1000 

也：

set @i=999; 
select @i:=@i+1 as num 
where @i <1999; 

Answer 1

你必須在一個有1000行的表操作，以獲得想要的東西：

SELECT @i := @i+1 AS num 
FROM (
    SELECT 1 AS x UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL 
    SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 AS x UNION ALL 
    SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 
) AS t 
CROSS JOIN (
    SELECT 1 AS x UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL 
    SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 AS x UNION ALL 
    SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 
) AS s 
CROSS JOIN (
    SELECT 1 AS x UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL 
    SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 AS x UNION ALL 
    SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 
) AS u 
CROSS JOIN (SELECT @i := 999) AS var 

在10使用CROSS JOIN 10 10表組合，我們得到一個1000行線表。以此爲基礎，我們可以計算所需的@i值的順序。

Demo here

Answer 2

我假設（可能是錯誤的）你試圖根據自動遞增的主鍵選擇行，看到這是MySQL？

「BETWEEN」關鍵字會更好用，而不是使用變量嗎？

例如，如果你想選擇表「mytable的」和「民」行是主鍵：

SELECT num FROM myTable 
WHERE num BETWEEN 999 AND 1999 

Answer 3

下面是一個簡單的查詢，打印數量1000 - 1999與一組增量值。

DECLARE @firstNumber INT 
DECLARE @lastNumber INT 
DECLARE @incrementBy INT 

SET @firstNumber = 1000 
SET @lastNumber = 1999 
SET @incrementBy = 1 

CREATE TABLE #TEMP (number INT) 

WHILE(@firstNumber <= @lastNumber) 
BEGIN 
    INSERT INTO #TEMP VALUES (@firstNumber) 
    SET @firstNumber = @firstNumber + @incrementBy 
END 

SELECT * FROM #TEMP 

DROP TABLE #TEMP