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我有一個簡單的PHP陣列稱爲$gatherArr
,看起來像這樣:PHP陣列和導航欄下拉列表
$gatherArr = [
["catCode"=>"ac", "catName"=>"Armchair"],
["catCode"=>"sf", "catName"=>"Sofa"],
["catCode"=>"st", "catName"=>"Side Table"],
["catCode"=>"ct", "catName"=>"Coffee Table"],
["catCode"=>"dt", "catName"=>"Table"],
["catCode"=>"cs", "catName"=>"Chair/Stool"],
["catCode"=>"sb", "catName"=>"Side Board"],
];
我想建立與PHP代碼中的菜單欄,並從$gatherArr
下拉列表。這是我的HTML代碼如下。
<div class="collapse navbar-collapse navHeaderCollapse">
<ul class="nav navbar-nav navbar-right">
<li class="active"><a href="index.php">About</a></li>
<li><a href="news.php">News</a></li>
<li class="dropdown">
<a href="#" class="dropdown-toggle" data-toggle="dropdown">Collection <b class="caret"></b></a>
<ul class="dropdown-menu">
<?php
include './productData.php';
foreach ($gatherArr as $name => $detail) {
echo" {$detail}<br />";
}
?>
</ul>
</li>
<li><a href="ordering.php">Ordering</a></li>
<li><a href="contactus.php">Contact</a></li>
</ul>
</div>
我在下拉菜單欄中顯示錯誤行。我也嘗試更改echo" {$detail}<br />"; To $name
,但我從菜單欄中獲得0 - 6的數字
謝謝!
感謝它的工作! – xhinvis