2012-12-09 43 views
43

我有一個PopupMenu,我知道通常的方式到菜單是使用popup.getMenuInflater().inflate(R.menu.my_menu, popup.getMenu());或類似的東西聯繫起來。我的問題是,我在菜單中有一些我想要的項目,我需要能夠用Java以編程方式更改它們。我怎樣才能做到這一點?設置PopupMenu的菜單項編程

謝謝!

回答

93

就想通了;任何人誰跑入你只是做同樣的問題:

popup.getMenu().add(groupId, itemId, order, title); 

您要添加的每個MenuItem

23

只需創建彈出式菜單中註冊視圖中的彈出窗口中將顯示下,使用使用getMenu()方法來添加值。不要忘記打電話給show();

PopupMenu menu = new PopupMenu(this, view); 

menu.getMenu().add("titleRes"); 
menu.show(); 
11

定義popupmenu.xml

<?xml version="1.0" encoding="utf-8"?> 
    <menu xmlns:android="http://schemas.android.com/apk/res/android" 
     xmlns:app="http://schemas.android.com/apk/res-auto"> 

     <item 
      android:id="@+id/slot1" 
      app:showAsAction="ifRoom|withText" 
      android:title="Movies" 
      android:visible="true"/> 
     <item 
      android:id="@+id/slot2" 
      app:showAsAction="ifRoom|withText" 
      android:title="Music" 
      android:visible="true"/> 
     <item 
      android:id="@+id/slot3" 
      app:showAsAction="ifRoom|withText" 
      android:title="Comedy" 
      android:visible="true"/> 

</menu> 

PopupMenu popupMenu = new PopupMenu(FullMenuActivity.this, view);      
popupMenu.setOnMenuItemClickListener(FullMenuActivity.this); 
popupMenu.getMenu().add(1, R.id.slot1, 1, "slot1"); 
popupMenu.getMenu().add(1,R.id.slot2,2,"slot2"); 
popupMenu.getMenu().add(1,R.id.slot3,3,"slot3"); 
popupMenu.show(); 

@Override 
    public boolean onMenuItemClick(MenuItem item) { 

     switch (item.getItemId()) { 
      case R.id.slot1: 
       SessionManager.selected_slot = item.getTitle().toString(); 
       Toast.makeText(this, "slot1 Clicked", Toast.LENGTH_SHORT).show(); 
       return true; 
      case R.id.slot2: 
       SessionManager.selected_slot = item.getTitle().toString(); 
       Toast.makeText(this, "slot2 Clicked", Toast.LENGTH_SHORT).show(); 
       return true; 
      case R.id.slot3: 
       SessionManager.selected_slot = item.getTitle().toString(); 
       Toast.makeText(this, "slot3 Clicked", Toast.LENGTH_SHORT).show(); 
       return true; 
      default: 
       return true; 
     } 
    } 
2

@Voora塔倫給了一個很好的答案ID和我此基礎上我的回答: 首先使用fa柯mune.xml資源,我認爲更好的辦法是創建ids文件,而不是:

ids.xml

<?xml version="1.0" encoding="utf-8"?> 
<resources> 
    <item name="menuGroup" type="id"/> 
    <item name="menu1" type="id"/> 
    <item name="menu2" type="id"/> 
    <item name="menu3" type="id"/> 
</resources> 

然後,你可以做這樣的事情:

private void showPopup(final View anchor) { 
     PopupMenu popupMenu = new PopupMenu(anchor.getContext(), anchor); 
     popupMenu.getMenu().add(R.id.menuGroup, R.id.menu1, Menu.NONE, "slot1"); 
     popupMenu.getMenu().add(R.id.menuGroup, R.id.menu1, Menu.NONE,"slot2"); 
     popupMenu.getMenu().add(R.id.menuGroup, R.id.menu1, Menu.NONE,"slot3"); 
     popupMenu.setOnMenuItemClickListener(new PopupMenu.OnMenuItemClickListener() { 
      @Override 
      public boolean onMenuItemClick(MenuItem item) { 
       Toast.makeText(anchor.getContext(), item.getTitle() + "clicked", Toast.LENGTH_SHORT).show(); 
       return true; 
      } 
     }); 
     popupMenu.show(); 
    } 
2

這裏是設置ID的完整解決方案並處理:

 this.findViewById(R.id.hamburger_menu).setOnClickListener(new View.OnClickListener() { 
      @Override 
      public void onClick(View v) { 
      PopupMenu menu = new PopupMenu(getApplicationContext(), v); 
      menu.getMenu().add(Menu.NONE, 1, 1, "Share"); 
      menu.getMenu().add(Menu.NONE, 2, 2, "Comment"); 
      menu.show(); 

      menu.setOnMenuItemClickListener(new PopupMenu.OnMenuItemClickListener() { 
       @Override 
       public boolean onMenuItemClick(MenuItem item) { 

        int i = item.getItemId(); 
        if (i == 1) { 
         //handle share 
         return true; 
        } else if (i == 2) { 
         //handle comment 
         return true; 
        } else { 
         return false; 
        } 
       } 

      }); 
     } 
    }); 

注:份額和註釋,例如,你也可以把一些常量,數字1,2使代碼更易讀。

而且,我把Menu.NONE,因爲我不關心分組的菜單項。如果你想組設置組ID = 1,2,等等

12

燁!它會幫助你。試試這個:)

Dynamic_PopUpMenu.setOnClickListener(新View.OnClickListener(){

​​3210