刪除支架和空字符串

Question

我是新來的java所以請在審查代碼時裸露在我身邊。

代碼的最終結果是能夠將字符串數組解析爲整數數組，但正如您所看到的，我得到一個異常。我嘗試拆分[和]符號，但是當我調用數組的第一個（0）元素splited_game_result [0]時，它不會返回任何內容。這裏有什麼解決方案？我嘗試使用修剪方法。

String[] ca_po_pe = {"4:7","PAUSE","2:0","1:3 PINE","PAUSE","CANCEL","2:4","0:5 PINE","PAUSE","CANCEL"}; 

    String canc_postp_pen_games = ""; 

    boolean confirming = true; 

    for(String looped_games : ca_po_pe) { 

    if(confirming) { canc_postp_pen_games+=looped_games; confirming=false; } 

    else { canc_postp_pen_games+=", "+looped_games; } } 

    System.out.println("LOOPED FINAL RESULT GAMES TO INSERT COMMAS: " + "\n" + canc_postp_pen_games + "\n"); 

    String[] fin_games_res = canc_postp_pen_games.split("[,]"); 

    ArrayList<String> arraylist= new ArrayList<String>(); 

    Collections.addAll(arraylist, fin_games_res); 

    for (String str: arraylist) {  
     } 

    System.out.println("ELEMENTS ADDED TO ARRAYLIST: " + arraylist + "\n"); 

int noItems = arraylist.size(); 

for (int i = 0; i < noItems; i++) { 

String currItem = arraylist.get(i); 

if (currItem.contains("PAUSE")) { 
arraylist.add(new String("400")); 
noItems++; } 

if (currItem.contains("CANCEL")) { 
arraylist.add(new String("300")); 
noItems++; } 

if (currItem.contains(" PINE")) { 
arraylist.add(new String("500")); 
noItems++; } 
    } 

    System.out.println("ELEMENTS BEFORE REMOVAL: " + "\n" + arraylist + "\n"); 

Iterator<String> iter_getting = arraylist.iterator(); 

while(iter_getting.hasNext()) { 

if(iter_getting.next().contains("PAUSE")){ 
    iter_getting.remove(); }} 

    Iterator<String> iter_getting1 = arraylist.iterator(); 

    while(iter_getting1.hasNext()) { 

if(iter_getting1.next().contains("CANCEL")){ 
    iter_getting1.remove(); }} 

    Iterator<String> iter_getting2 = arraylist.iterator(); 

    while(iter_getting2.hasNext()) { 

if(iter_getting2.next().contains(" PINE")){ 
    iter_getting2.remove(); }} 

    System.out.println("ELEMENTS AFTER REMOVAL: " + "\n" + arraylist); 

    System.out.println("ELEMENT ON INDEX 3 BEFORE CONVERTION TO ARRAY: " + "\n" + arraylist.get(3)); 

    String convert = arraylist.toString(); 

    System.out.println("CONVERTED STRING: " + convert); 

    String[]splited_game_result = convert.trim().split("[\\[:,\\]]"); 

    System.out.println(" AFTER SPLITING TO ARRAY: " + "\n" + splited_game_result[0]); 

    Integer[] final_result = new Integer[splited_game_result.length]; 

    int g = 0; 

    for(String fsgr : splited_game_result) 

{final_result [g] = Integer.parseInt（fsgr）; g ++;}

System.out.println("INTEGER ELEMENT ON INDEX 0: " + "\n" + final_result[1]);  

Answer 1

對於大家誰懷疑，異常源的盡頭升起。它說NumberFormatException: For input string: ""。見下文源：

for(String fsgr : splited_game_result) 
{ final_result[g] = Integer.parseInt(fsgr); g++;} 

的原因是在用於分割陣列經常expession作者：

String[]splited_game_result = convert.trim().split("[\\[:,\\]]"); 

它產生字符串以下數組：
["", "4", "7", " 2", "0", " 2", "4", " 400", " 500", " 400", " 300", " 500", " 400", " 300"]

問題是Integer.parseInt要求string that contain parsable integer

可能的工作臺ound是添加if condition，以確保您的fsgr不是一個空字符串，並且不包含空格：

for(String fsgr : splited_game_result) { 

    String fsgrTrim = fsgr.trim(); 

    if (!fsgrTrim.isEmpty()) { 
     final_result[g] = Integer.parseInt(fsgrTrim); 
     g++; 
    } 
} 

或添加的try-catch子句：

for(String fsgr : splited_game_result) { 
    try { 
     final_result[g] = Integer.parseInt(fsgr); 
     g++; 
    } catch (Exception e) { 
     e.printStackTrace(); 
    } 
} 

Answer 2

我仍然不知道你要做什麼，但這裏是你的例外。您正在解析一個空字符串，並嘗試解析數字前的空格。爲您的邏輯發表評論。

for (String fsgr : splited_game_result) { 
    try { 
     final_result[g] = Integer.parseInt(fsgr); 
     g++; 
    } catch(Exception e2) { 
     System.out.println("Exception = ["+ fsgr + "]"); 
    } 
} 

輸出（在看跌期權的中間。使用第一個和最後printlns的位置）

CONVERTED STRING: [4:7, 2:0, 2:4, 400, 500, 400, 300, 500, 400, 300] 
AFTER SPLITING TO ARRAY: 

Exception = [] 
Exception = [ 2] 
Exception = [ 2] 
Exception = [ 400] 
Exception = [ 500] 
Exception = [ 400] 
Exception = [ 300] 
Exception = [ 500] 
Exception = [ 400] 
Exception = [ 300] 
INTEGER ELEMENT ON INDEX 0: 
7