結合了兩種SQL查詢到1

Question

我有一個快速的問題...

我想兩個SQL查詢合併成一個，但問題是，這兩個查詢具有GROUP BY在裏面。

查詢1：

SELECT COUNT(users_survey_answers.ultimate_survey_code) 
FROM  company, 
     users_codes, 
     users_survey_answers 
WHERE company.company_id = users_codes.company_id 
    AND users_codes.email = "test@gmail.com" 
    AND users_codes.company_id = users_survey_answers.company_id 
    AND users_survey_answers.completed = 0 
GROUP BY users_codes.company_id 

查詢2：

SELECT COUNT(users_rewards.reward_id) 
FROM  company, 
     users_codes, 
     users_rewards 
WHERE company.company_id = users_codes.company_id 
    AND users_codes.email = "test@gmail.com" 
    AND users_rewards.company_id = users_codes.company_id 
    AND redeemed = 0 
GROUP BY users_codes.company_id 

我欣賞的幫助。我已經嘗試了很多解決方案，仍然沒有幫助。

謝謝。

Answer 1

試試這個：

SELECT company.company_id, 
      users_pts.pts as CompanyPts, 
      t1.ultimate_survey_code_count, 
      t2.reward_id_count 
FROM  company, 
      users_codes 
INNER JOIN (
      SELECT 
       company_id, 
       COUNT(ultimate_survey_code) AS ultimate_survey_code_count 
      FROM users_survey_answers 
      WHERE completed = 0 
      GROUP BY company_id 
     ) AS t1 
     ON users_codes.company_id = t1.company_id 
INNER JOIN (
      SELECT 
       company_id, 
       SUM(IF(redeemed = 0, 1, 0)) AS reward_redeem_zero_count, 
       SUM(IF(redeemed = 0, 0, 1)) AS reward_redeem_not_zero_count 
      FROM users_rewards 
      GROUP BY company_id 
     ) AS t2 
     ON users_codes.company_id = t2.company_id 
INNER JOIN users_pts 
     ON users_codes.company_id = users_pts.company_id 
WHERE  company.company_id = users_codes.company_id 
    AND  users_codes.email = "test@gmail.com" 

這是未經測試，但希望能滿足您的需要。

Answer 2

我把增加 company_id到選擇的libery。如果事後不能說出哪個公司屬於哪個結果，那麼通過company_id進行分組有什麼好處。 :)

select 
    company_id, 
    sum(code_count) as code_count, 
    sum(reward_count) as reward_count 
FROM 
    (SELECT 
     users_codes.company_id, 
     COUNT(users_survey_answers.ultimate_survey_code) as code_count, 
     null as reward_count 
    FROM  company, 
      users_codes, 
      users_survey_answers 
    WHERE company.company_id = users_codes.company_id 
     AND users_codes.email = "test@gmail.com" 
     AND users_codes.company_id = users_survey_answers.company_id 
     AND users_survey_answers.completed = 0 
    GROUP BY users_codes.company_id 
    UNION ALL 
    SELECT 
     users_codes.company_id, 
     COUNT(users_rewards.reward_id) as reward_count, 
     null 
    FROM  company, 
      users_codes, 
      users_rewards 
    WHERE company.company_id = users_codes.company_id 
     AND users_codes.email = "test@gmail.com" 
     AND users_rewards.company_id = users_codes.company_id 
     AND redeemed = 0 
    GROUP BY users_codes.company_id) x 
GROUP BY 
    company_id 

太麻煩了。你可以這樣寫。 我還冒昧地引入了更現代的INNER JOIN以及鋸齒，但隨時可以恢復。

SELECT 
    c.company_id, 
    (SELECT COUNT(ultimate_survey_code) 
    FROM 
    users_survey_answers a 
    WHERE 
    a.completed = 0 AND 
    a.company_id = c.company_id) as answer_count, 
    (SELECT COUNT(ultimate_survey_code) 
    FROM 
    users_rewards r 
    WHERE 
    r.redeemed = 0 AND 
    r.company_id = c.company_id) as reward_count 
FROM 
    company c 
    INNER JOIN users_code uc ON uc.company_id = c.company_id 
WHERE 
    uc.email = "test@gmail.com" 
GROUP BY 
    c.company_id