如何運行多時間相同的代碼中的Bash

Question

我怎麼能多次運行相同的代碼？例如12次？

sed -n 1,1p 00-02.txt | sed -e 's/^/<video length="-1" src="mp4:/' \ 
          -e 's/$/" start="0"><\/video>/' >>playlist.txt 

    echo -e "$(sed -e '1,1d' 00-02.txt)\n" > 00-02.txt 

    cat 00-02.txt | sed '/^$/d' >> 00-02a.txt 

    rm 00-02.txt 

    mv 00-02a.txt 00-02.txt 

    sed -n 1,1p spot.txt | sed -e 's/^/<video length="-1" src="mp4:/' \ 
          -e 's/$/" start="0"><\/video>/' >>playlist.txt 

    echo -e "$(sed -e '1,1d' spot.txt)\n" > spot.txt 

    cat spot.txt | sed '/^$/d' >> spota.txt 

    rm spot.txt 

mv spota.txt spot.txt 

所有代碼belove必須複製N次

像

for n in {1..12}; **ALL THE COMMANDS BELOVE**; done 

但它不爲命令的多行工作。

任何問題？

Answer 1

使用while循環和計數器：

#!/bin/bash 

iterations=12 
count=0 

while [ "$count" -lt "$iterations" ] 
do 
    sed -n 1,1p 00-02.txt | sed -e 's/^/<video length="-1" src="mp4:/' \ 
         -e 's/$/" start="0"><\/video>/' >>playlist.txt 

    echo -e "$(sed -e '1,1d' 00-02.txt)\n" > 00-02.txt 

    cat 00-02.txt | sed '/^$/d' >> 00-02a.txt 

    rm 00-02.txt 

    mv 00-02a.txt 00-02.txt 

    sed -n 1,1p spot.txt | sed -e 's/^/<video length="-1" src="mp4:/' \ 
         -e 's/$/" start="0"><\/video>/' >>playlist.txt 

    echo -e "$(sed -e '1,1d' spot.txt)\n" > spot.txt 

    cat spot.txt | sed '/^$/d' >> spota.txt 

    rm spot.txt 

    mv spota.txt spot.txt 
    count=$((count + 1)) 
done 

Answer 2

你可以使用seq：

for i in $(seq 1 12) ; do echo $i ; done 

這不是一個內置的，但它是一個很常見的實用工具。