檢查PSObject中的空數組

我該如何去檢查具有多個數組的對象中的空或空？檢查PSObject中的空數組

$buildings.North = {bld1,bld2,bld3} 
$buildings.South = {} 
$buildings.East = {bld5,bld6} 
$buildings.West = {bld7,bld8,bld9,bld10}

我開始了一個IF/ELSEIF要經過每一個，但是這將是這16種組合：

if ($Buildings.North.count -eq "0" -and $Buildings.South.count -ge "1" -and $Buildings.East.count -ge "1" -and $Buildings.West.count -ge "1"){set-function -OPT1 $Buildings.South -OPT2 $Buildings.East -OPT3 $Buildings.West } 
elseif ($Buildings.North.count -ge "1" -and $Buildings.South.count -ge "1" -and $Buildings.East.count -ge "1" -and $Buildings.West.count -ge "1"){set-function -OPT1 $Buildings.North -OPT2 $Buildings.South -OPT3 $Buildings.East -OPT4 $Buildings.West} 
elseif ($Buildings.North.count -eq "0" -and $Buildings.South.count -eq "0" -and $Buildings.East.count -eq "0" -and $Buildings.West.count -eq "0"){#empty do nothing} 
elseif ($Buildings.North.count -eq "0" -and $Buildings.South.count -eq "0" -and $Buildings.East.count -ge "1" -and $Buildings.West.count -ge "1"){set-function -OPT3 $Buildings.East -OPT4 $Buildings.West}

既然你可能有數百個選項的對象，這可能有很多代碼。我也嘗試從字符串中構建cmd：

$cmd = ' -Location $Loc' 
if ($Buildings.North.count -ge "1"){ $cmd += ' -OPT1 $Buildings.North ' } 
elseif ($Buildings.South.count -ge "1"){$cmd += ' -OPT2 $Buildings.South'} 
elseif ($Buildings.East.count -ge "1"){$cmd += ' -OPT3 $Buildings.East'} 
elseif ($Buildings.West.count -ge "1"){$cmd += ' -OPT4 $Buildings.West'} 
Set-Function $cmd

這種方法也沒有太大的成功。必須有更好的方法來進行這種檢查，幫助找到它將是最受讚賞的。

來源

2013-03-20 user1178954

這應該工作：

$cmd = ' -Location `$Loc' 
if ($Buildings.North.count -ge "1"){ $cmd += ' -OPT1 `$Buildings.North ' } 
elseif ($Buildings.South.count -ge "1"){$cmd += ' -OPT2 `$Buildings.South'} 
elseif ($Buildings.East.count -ge "1"){$cmd += ' -OPT3 `$Buildings.East'} 
elseif ($Buildings.West.count -ge "1"){$cmd += ' -OPT4 `$Buildings.West'} 
Invoke-Expression "Set-Function $cmd"

來源

2013-03-20 21:32:42

調用，表達！啊！這有助於使功能正常工作。謝謝。你碰巧對如何在這種類型的對象設置中檢查null（或不爲空）有任何想法。我開始越來越多地使用對象，並且我不能想出一種方法來做這種檢查，而不是很長的if/elseif條件。 – user1178954 2013-03-20 21:48:06

@ user1178954：如果它解決了您的問題，請不要忘記將此答案標記爲已接受。 – Neolisk 2013-03-21 00:14:01

$Opts = @{ 
OPT1 = $buildings.North 
OPT2 = $buildings.South 
OPT3 = $buildings.East 
OPT4 = $buildings.West 
} 

$opts.GetEnumerator() | 
foreach {if (-not $_.value){$opts.Remove($_.Name)}} 

Set-Function @Opts

FWIW

來源

2013-03-20 22:53:20 mjolinor

謝謝！這對於這種事情很有效。 – user1178954 2013-03-21 12:27:38

#Create Test Object 
$buildings = New-Object -TypeName psobject -Property @{'North'[email protected]('a','b');'south'[email protected]('x');'West'[email protected]()} 

#Returns arrays that are not 0 in count 
$buildings | Get-Member -MemberType NoteProperty | ? {($buildings.($_.name)).count}

來源

2013-03-21 05:23:37

檢查PSObject中的空數組

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