查找最新的文件開始

Question

我會希望結合功能找到最近的文件開始：

$path = "/home/www/images/xml_cache"; 
$nom="images_album_6*.xml"; 

foreach (glob($path.'/'.$nom.'') as $filename) { } 

和

$latest_ctime = 0; 
    $latest_filename = ''; 
    $d = dir($path); 
    while (false !== ($entry = $d->read())) { 
    $filepath = "{$path}/{$entry}"; 
    // could do also other checks than just checking whether the entry is a file 
    if (is_file($filepath) && filectime($filepath) > $latest_ctime) { 
     $latest_ctime = filectime($filepath); 
     $latest_filename = $entry; 
    } 
    } 
} 

怎麼會呢？

預先感謝您

Answer 1

假設你有PHP5，您可以使用RecursiveIterator類與getMTime功能組合：

$path = "/home/www/images/xml_cache"; 
$pattern = "/^images_album_6\S+.xml/i"; 
$latest_time = 0; 
$latest_filename = ''; 
$iterator = new RecursiveIteratorIterator(new RecursiveDirectoryIterator($path), RecursiveIteratorIterator::CHILD_FIRST); 
foreach ($iterator as $file) { 
    if ($file->isFile() && preg_match($pattern,$file->getFilename())) { 
     if ($file->getMTime() > $latest_time) { 
      $latest_time = $file->getMTime(); 
      $latest_filename = $file->getPathname(); 
     } 
    } 
} 
print("Latest file: ".$latest_filename.PHP_EOL); 

這將遞歸檢查您指定的路徑和打印的完整路徑最新的文件匹配您的文件名稱模式。