如何比較2個文件夾，如果文件丟失採取措施？

Question

我正在使用一個腳本來調整大小的照片到另一個文件夾，並保持相同的名稱automaticaly發現here和工作很好！

我在我的源文件夾中有數百張照片，我打算經常執行此操作。我想通過僅在看到照片不存在於目標文件夾中的情況下調整照片大小來優化時間。我們怎麼做到這一點？

這裏使用的全碼：

function imageResize($file, $path, $height, $width) 
{ 

     $target = 'smallphotos/'; 

     $handle = opendir($path); 

     if($file != "." && $file != ".." && !is_dir($path.$file)) 
     { 

       $thumb = $path.$file; 

       $imageDetails = getimagesize($thumb); 

       $originalWidth = $imageDetails[0]; 

       $originalHeight = $imageDetails[1]; 

       if($originalWidth > $originalHeight) 
       { 

        $thumbHeight = $height; 

        $thumbWidth = ($originalWidth/($originalHeight/$thumbHeight)); 

       } 
       else 
       { 

        $thumbWidth = $width; 

        $thumbHeight = ($originalHeight/($originalWidth/$thumbWidth)); 

       } 

       $originalImage = ImageCreateFromJPEG($thumb); 

       $thumbImage = ImageCreateTrueColor($thumbWidth, $thumbHeight); 

       ImageCopyResized($thumbImage, $originalImage, 0, 0, 0, 0, $thumbWidth, 
       $thumbHeight, $originalWidth, $originalHeight); 

       $filename = $file; 

       imagejpeg($thumbImage, $target.$filename, 100); 

     } 

     closedir($handle); 

} 

    $source = "photos"; 

    $directory = opendir($source); 

    //Scan through the folder one file at a time 

    while(($file = readdir($directory)) != false) 
    { 

      echo "<br>".$file; 

      //Run each file through the image resize function 

      imageResize($file, $source.'/', 640, 480); 

    } 

Answer 1

好像你只需要添加一個條件調整大小功能

if ($file != "." && $file != ".." && !is_dir($path.$file) && !is_file($target.$file) {... 

這應該保持它嘗試，如果做任何事情目標文件已經存在。

另一種選擇是，以檢查目標文件調用該函數

while (($file = readdir($directory)) != false) { 
    echo "<br>".$file; 
    //Run each file through the image resize function (if it has not already been resized) 
    if (!is_file("smallphotos/$file")) { 
     imageResize($file, $source.'/', 640, 480); 
    } 
}