如何在ASP.net中使用for循環生成字符串？

Question

我通過循環該列表生成jQuery的字符串如下

events: [ 
     { 
      title: 'All Day Event', 
      start: '2014-11-01' 
     }, 
     { 
      title: 'Long Event', 
      start: '2014-11-07', 
      end: '2014-11-10' 
     }, 
     { 
      id: 999, 
      title: 'Repeating Event', 
      start: '2014-11-09T16:00:00' 
     }, 
     { 
      id: 999, 
      title: 'Repeating Event', 
      start: '2014-11-16T16:00:00' 
     }, 
     { 
      title: 'Conference', 
      start: '2014-11-11', 
      end: '2014-11-13' 
     }, 
     { 
      title: 'Meeting', 
      start: '2014-11-12T10:30:00', 
      end: '2014-11-12T12:30:00' 
     }, 
     { 
      title: 'Lunch', 
      start: '2014-11-12T12:00:00' 
     }, 
     { 
      title: 'Meeting', 
      start: '2014-11-12T14:30:00' 
     }, 
     { 
      title: 'Happy Hour', 
      start: '2014-11-12T17:30:00' 
     } 
    ] 

列表包含這些元素，但我無法產生這種字符串的.I've試圖以兩種方式

for(var i=0; i<customers.length; i++) 
      { 
      "{" 

       "title:" +customers[i].Column1+"," 
       "start:"+customers[i].Column3 
       "}" 


      if(i!=customers.length-1) 
      { 
       "," 
      } 

      } 

和

  $.each(eventList, function (index, employee) { 
     { 
     title:employee.name, 
     start:employee.date 
     } 
    , 
     }); 

，但我無法得到正確的結果，請給我解決這個。要獲取列表我使用下面的COE

$(document).ready(function() { 
    $.ajax({ 
     type: 'POST', 
     dataType: 'json', 
     contentType: 'application/json', 
     url: 'ProjectedYieldCalender.aspx/GetData', 
     data: '{}', 
     success: 
      function (data) { 

       var eventList = data.d 
       eventList=demo(eventList); 
       initCalendar(eventList); 
      } 

    }); 

}); 
function initCalendar(eventList) { 
    $('#calendar').fullCalendar({ 
    header: { 
     left: 'prev,next today', 
     center: 'title', 
     right: 'month,basicWeek,basicDay' 
    }, 
    //defaultDate: '2014-08-12', 
    editable: true, 
    eventLimit: true, // allow "more" link when too many events 
    events: [ 
     eventList 
    ] 
}); 


} 

謝謝

Answer 1

你想要的所有事件是單一事件。那麼這可能有幫助。

var string; 
$.each(events, function() { 
string += "{title:" + this.title + "start:" + this.start + "}" ; 
});