如何從aplay -l的字符串輸出中獲取值1,0？

我有這個字符串輸出，在那裏我試圖得到輸出值爲：1,0通過刪除所有其餘。如何從aplay -l的字符串輸出中獲取值1,0？

ex。

$ aplay -l | grep "C-Media USB Audio Device" 
card 1: Device [C-Media USB Audio Device], device 0: USB Audio [USB Audio] 

$ aplay -l | grep "C-Media USB Audio Device" | awk '{print $2}' 
1: 

$ aplay -l | grep "C-Media USB Audio Device" | awk '{print $9}' 
0:

但是，如何一次獲得值爲1,0？即使字符串比較大，但是在任何地方都有卡和設備？

例如：錯誤

$ aplay -l 
**** List of PLAYBACK Hardware Devices **** 
card 0: PCH [HDA Intel PCH], device 0: CA0132 Analog [CA0132 Analog] 
    Subdevices: 0/1 
    Subdevice #0: subdevice #0 
card 0: PCH [HDA Intel PCH], device 3: HDMI 0 [HDMI 0] 
    Subdevices: 1/1 
    Subdevice #0: subdevice #0 
card 1: Device [C-Media USB Audio Device], device 0: USB Audio [USB Audio] 
    Subdevices: 1/1 
    Subdevice #0: subdevice #0 
card 2: NVidia [HDA NVidia], device 3: HDMI 0 [HDMI 0] 
    Subdevices: 1/1 
    Subdevice #0: subdevice #0 

$ aplay -l | grep "HDA NVidia" | perl -anE 's/://g, say for $t="$F[1],$F[8]"' 
2,0 
$ aplay -l | grep "HDA Intel PCH" | perl -anE 's/://g, say for $t="$F[1],$F[8]"' 
0,CA0132 
0,HDMI 
$ aplay -l | grep "C-Media USB Audio Device" | perl -anE 's/://g, say for $t="$F[1],$F[8]"' 
1,0

來源

2013-05-31 YumYumYum

aplay -l | grep "C-Media USB Audio Device" | perl -anE 's/://g, say for $t="$F[1],$F[8]"'

和其他設備將刪除[]和:字符之間的一切，

aplay -l | grep "C-Media USB Audio Device" | perl -nE 's/ \[.*?\] | : //xg; say join",",(split)[1,5];'

來源

2013-05-31 07:45:09

當我有不同的USB麥克風或例如聲卡失敗在這種情況下：$ aplay -l | grep「C-Media USB音頻設備dsffd dfdsadfds sfdsfdsfd」| perl -anE的/：// g，比如說$ t =「$ F [1]，$ F [8]」' – YumYumYum

如何從aplay -l的字符串輸出中獲取值1,0？

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