2014-03-24 32 views
0

我想文字和變量qDebug結合:文字+變量qDebug

QString city_name = "London"; 
qDebug() << QString("You choose CITY:").arg(city_name); 

它不工作,我不知道爲什麼。錯誤是:

QString::arg: Argument missing: You choose CITY:, ????? 

回答

0

添加%1:

QString city_name = "London"; 
qDebug() << QString("You choose CITY: %1").arg(city_name);