jQuery的點擊更改事件顯示，交換

我正試圖讓更改事件在下拉菜單上交換。如果有人隱藏，我希望它顯示值匹配時，反之亦然。目前，一旦隱藏，價值改變，它仍然隱藏。請幫忙。切換不適合我。jQuery的點擊更改事件顯示，交換

<label for="filter-select"> Issue Type: </label> 
<select class="filter" id="filter-select" name="filtering"> 
    <option selected="selected">Any</option> 
    <option value="incident">Incidents</option> 
    <option value="feature">Feature Requests</option> 
</select>

$(".sort > tr > td:nth-child(1)").each(function(){ 
    var textid = $(this).text(); 
    $(this).attr('id', textid); 
    var id = $(this).attr('id'); 
    $(".sort > tr").each(function(){ 
var ide = $(this).children('td:nth-child(1)').attr('id'); 
$(this).attr('id', ide); 

}); 

var username = "[email protected]" 
var password = "DpcMixcolt12!!" 
var formurl = "/api/v2/requests/"+id+".json)"; 
function make_base_auth(user, password) { 
var tok = user + ':' + password 
var hash = btoa(tok); 
return "Basic " + hash; 
}  

$.ajax({ 
type: 'GET', 
url: formurl, 
datatype: "json", 
beforeSend: function (xhr) { 
xhr.setRequestHeader('Authorization',make_base_auth(username, password)); 

}, 
success: function (result) { 

$.each(result, function(i, value) { 

$('.filter').change(function() { 
    if ($(this).val() =='any') { 
     $('.sort > tr').each(function() { 
      $(this).show(); 
     }); 
    } 

    if ($(this).val() === 'incident') { 
     $('.sort > tr').each(function() { 
      if (value.ticket_form_id == '59229' & value.id == $(this).attr('id')) { 
       console.log('incident', $(this).attr('id')); 
       $(this).toggle(); 
      } 
     }); 
    } 
    else if ($(this).val() === 'feature') { 
     $('.sort > tr').each(function() { 
      if (value.ticket_form_id == '39365' & value.id == $(this).attr('id')) { 
       console.log('new feature', $(this).attr('id')); 
       $(this).toggle(); 
      } 
     }); 
    }  
    }); 
    }) 
} 
}); 
});

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