package blurbProject;
import java.util.Random;
import java.util.Scanner;
public class BlurbMaker
{
Random generator = new Random(); //"Random" number generator for the Whatzits
public BlurbMaker()//constructor
{
generator = null;
}//close constructor
public BlurbMaker(Random iniGenerator)//initialize constructor
{
generator = iniGenerator;
}//close initialization
private String getWhoozitYs(){
StringBuffer sb = new StringBuffer();
boolean stop = generator.nextBoolean(); //NullPointerException here
if(stop == true)
{
sb.append("y");
getWhoozitYs();
}
return sb.toString();
}
private String getWhozit()
{
StringBuffer sb = new StringBuffer();
sb.append("x");
sb.append(getWhoozitYs()); //NullPointerException here
return sb.toString();
}
private String getWhatzit()
{
StringBuffer sb = new StringBuffer();
sb.append("q");
boolean stop = generator.nextBoolean();
if(stop == true)
{
sb.append("z");
}
else
{
sb.append("d");
}
sb.append(getWhozit()); //NullPointerException here
return sb.toString();
}
private String getMultipleWhatzits()
{
StringBuffer sb = new StringBuffer();
sb.append(getWhatzit());
boolean stop = generator.nextBoolean();
if(stop == true)
{
sb.append(getWhatzit());
}
else
{
sb.append("");
}
return sb.toString();
}
public String generateBlurb()
{
StringBuffer sb = new StringBuffer();
sb.append(getWhozit());
sb.append(getMultipleWhatzits());
return sb.toString();
}
public static void main(String[] args)
{
BlurbMaker blurbmaker = new BlurbMaker();
Scanner scanner = new Scanner(System.in);
System.out.print("How many blurbs would you like? ");
int blurbNumber = scanner.nextInt();
if(blurbNumber > 0)
for(int i = 0; i < blurbNumber; i++){
System.out.println("Blurb: " + blurbmaker.generateBlurb());
//NullPointerException on line above
}
else
System.out.println("My work here is done.");
scanner.close();
}//close main
}//close class
我正在爲一個編程類的項目工作,並試圖運行此程序後,我在這裏的代碼中列出的四行上得到NullPointerExceptions。我知道一個NullPointerException來自嘗試訪問null的東西,但我不知道如何解決它。如何解決這個NullPointerException?
super()不會做任何事情,該類不會從Object繼承任何東西。你是說這個()? – Adrian 2013-03-14 15:36:36
好吧,是的,會使用'this()',但沒有意義創建一個不會被使用的新Random':)。:) – Reimeus 2013-03-14 15:39:03