MySQL的選擇情況下不得使用功能

Question

工作如何存儲在圖像1可變

BEGIN 
DECLARE image1 VARCHAR(250); 
select case when (
      (
       select COUNT(*) 
       from profile_images 
       where building_id = bid 
        and contractor_id = cid 
       ) > 0 
      ) then (
       select distinct (image) 
       into image1 
       from profile_images 
       where building_id = bid 
        and contractor_id = cid limit 1 
       ) else (
      select distinct (image) 
      into image1 
      from profile_images 
      where contractor_id = cid limit 1 
      ) 

END 
RETURN image1; 
END 

Answer 1

嘗試值：

BEGIN 
DECLARE image1 VARCHAR(250); 
select case when 
      (
       select COUNT(*) 
       from profile_images 
       where building_id = bid 
        and contractor_id = cid 
       ) > 0 
       then (
       select distinct (image) 
       -- into image1 
       from profile_images 
       where building_id = bid 
        and contractor_id = cid limit 1 
       ) else (
      select distinct (image) 
      -- into image1 
      from profile_images 
      where contractor_id = cid limit 1 
      ) 
END into image1; 
RETURN image1; 
END