MySQL的INSERT ... ON DUPLICATE KEY沒有更新的表沒有錯誤或警告

Question

所以，我有如下表：

mysql> show create table user_api_skills \G 
*************************** 1. row *************************** 
     Table: user_api_skills 
Create Table: CREATE TABLE `user_api_skills` (
    `characterID` int(11) NOT NULL, 
    `typeID` int(11) NOT NULL, 
    `level` enum('0','1','2','3','4','5') NOT NULL DEFAULT '0', 
    `skillpoints` int(11) NOT NULL, 
    `currentTime` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, 
    PRIMARY KEY (`characterID`,`typeID`) 
) ENGINE=InnoDB DEFAULT CHARSET=latin1 
1 row in set (0.00 sec) 

mysql> 

並在表中的一行，我正在嘗試插入/更新：

mysql> SELECT * FROM `user_api_skills` WHERE `characterID` =93192782 AND `typeID` =3359; 
+-------------+--------+-------+-------------+---------------------+ 
| characterID | typeID | level | skillpoints | currentTime   | 
+-------------+--------+-------+-------------+---------------------+ 
| 93192782 | 3359 | 3  |  135765 | 2013-09-30 16:58:35 | 
+-------------+--------+-------+-------------+---------------------+ 
1 row in set (0.00 sec) 

我認爲是正確形成我的查詢，並在執行時會不會引發任何錯誤或警告：

mysql> INSERT INTO user_api_skills (characterID,typeID,level,skillpoints) 
VALUES (93192782,3359,4,135765) ON DUPLICATE KEY UPDATE level=4,    
skillpoints=135765,currentTime=NOW(); 
Query OK, 2 rows affected (0.22 sec) 

我得到2行更新（因爲我會從DUP更新插入預期）

mysql> SELECT * FROM `user_api_skills` WHERE `characterID` =93192782 AND `typeID` =3359; 
+-------------+--------+-------+-------------+---------------------+ 
| characterID | typeID | level | skillpoints | currentTime   | 
+-------------+--------+-------+-------------+---------------------+ 
| 93192782 | 3359 | 3  |  135765 | 2013-09-30 16:59:13 | 
+-------------+--------+-------+-------------+---------------------+ 
1 row in set (0.00 sec) 

mysql> 

，但該行本身只改變單一值（currentTime的）。任何人都可以解釋爲什麼其他兩個字段沒有更新？

Answer 1

對不起，我自己解決了這個問題。級別字段是ENUM，查詢將新值指定爲數字。將查詢更新爲以下內容會產生預期的結果。

mysql> INSERT INTO user_api_skills (characterID,typeID,level,skillpoints) VALUES 
(93192782,3359,4,135765) ON DUPLICATE KEY UPDATE level='4', skillpoints=135765, 
currentTime=NOW(); 

通過提供一個int值以更新其更新到一個基於數量的選擇枚舉的，所以在這種情況下，第4個選項是「3」。