neo4j如何與兩個匹配工作

Question

我有兩個疑問。

第一個查詢

match (user)-[r:CreatesChat]-(chatitems) 

第二個查詢

match (chatitems)-[r:PartOf]-(teamschat)-[s:OwnedBy]-() 

我想第一個3個用戶從第一個查詢

，並從第二返回第3隊返回查詢

目標是檢查第一個查詢的用戶是否有se COND查詢

我的Neo4j查詢

match (user)-[r:CreatesChat]-(chatitems) 
with user.id as uid,chatitems.id as chatid 
order by uid desc 
with collect([uid])[..3] as users,collect([chatid])[..3] as chats 
UNWIND users AS idusers 
match (chatitems)-[r:PartOf]-(teamschat)-[s:OwnedBy]-() 
return idusers 

該查詢返回

返回133239排在1360毫秒，顯示第1000行

但我執行查詢

match (user)-[r:CreatesChat]-(chatitems) 
with user.id as uid,chatitems.id as chatid 
order by uid desc 
with collect([uid])[..3] as users,collect([chatid])[..3] as chats 
UNWIND users AS idusers 
return idusers 

idusers retu rned are right

在539毫秒內返回3行。

我如何關聯這兩個查詢？

Answer 1

我想你想收集前3名用戶和前3名球隊，然後放鬆每一個收集。類似這樣的：

MATCH (user:User)-[:CreatesChat]->(chatitems:Chat) 
WITH user ORDER BY user.id DESC LIMIT 3 
WITH collect(user) AS users 
MATCH (chatitems:Item)-[:PartOf]->(teamsChat:Team)-[:OwnedBy]-() 
WITH users, teamsChat ORDER BY teamsChat.id DESC LIMIT 3 
WITH users, collect(teamsChat) AS teams 
UNWIND users AS user 
UNWIND teams AS team 
MATCH p=(chatitems:Item)-[:PartOf]-(team)-[:OwndedBy]-(user) 
RETURN p