如何使用cpp程序將值插入數據庫（mySql）？

Question

void SignUp() 
{ 
    MYSQL* conn; 
    MYSQL_ROW row; 
    MYSQL_RES* res; 
    int nQueryState = 0; 
    int nId   = 0; 
    char szName[45]; 
    char szPassWord[45]; 
    char szQuestion[45]; 
    char szPhone[45]; 

    cout<<"Enter the Id"; 
    cin>>nId; 

    cout<<"Enter the Name"; 
    cin>>szName; 

    cout<<"Enter the Password"; 
    cin>>szPassWord; 

    cout<<"Enter the Question"; 
    cin>>szQuestion; 

    cout<<"Enter the Phone"; 
    cin>>szPhone; 

conn = mysql_init(0); 
conn =mysql_real_connect(conn,"localhost","root","12356","hari",0,NULL,0); 
nQueryState = mysql_query(conn,"insert into userdetails values(nId,szName,szPassword,szQuestion,szPhone)"); 

if(0!=nQueryState) 
{ 
    cout<<"\n\nConnection not Established"; 
} 
} 

我想輸入詳細信息到名爲userdetails的表中。它給了我一個輸出，使得連接不被建立。請通過它並幫助我。我使用的代碼塊IDE和mySql5.1

Answer 1

嘗試如下：

MYSQL mysql,*connection; 
MYSQL_RES result; 
MYSQL_ROW row; 


mysql_init(&mysql); 
connection =mysql_real_connect(&mysql,"localhost","root","12356","hari",0,NULL,0); 

if (connection==NULL) 
{ 
    cout<<mysql_error(&mysql)<<endl; 
} 
else{ 
    nQueryState = mysql_query(&mysql,"insert into userdetails values('"+nId+"','"+szName+"','"+szPassword+"','"+szQuestion+"','"+szPhone+"')"); 

    if (nQueryState !=0) { 
    cout << mysql_error(connection) << endl; 
    return 1; 
    } 
} 

mysql_close(&mysql); 

參見：http://www.codeproject.com/Questions/337901/How-to-insert-data-in-database-using-Cplusplus