PHP替換字符串

一定數目的字符我有哪裏我試圖掩蓋用戶的電子郵件的一部分與***PHP替換字符串

$user_email       = [email protected] 

$unmasked_user_email_array   = explode('@', $user_email); 
$unmasked_user_email_string   = $unmasked_user_email[0]; 
$unmasked_user_email_string_length = strlen($unmasked_user_email_string); 

if ($unmasked_user_email_string_length > 4) { 
    replace the last three characters of $unmasked_user_email_string with *** 
} 
else if ($unmasked_user_email_string_length < 5) { 
    replace the last two characters of $unmasked_user_email_string with ** 
} 
else if ($unmasked_user_email_string_length < 4) { 
    replace the last one character of $unmasked_user_email_string with * 
}

我的問題是，我應該用什麼方法或功能的當前代碼能夠完成我想要做的事情嗎？

感謝

來源

2014-10-07 user2028856

故障：$ unmasked_user_email_string = $ unmasked_user_email [0] ;應該是$ unmasked_user_email_string = $ unmasked_user_email_array [0]; – 2014-10-07 07:16:58

謝謝，我糾正了在我的生產代碼:) – user2028856 2014-10-07 07:20:46

這將這樣的伎倆爲您服務。使用PHP本地函數substr（）刪除最後幾個字符。然後我們在爲隱藏的元素添加一些星星後重建電子郵件地址。此外，您的$ unmasked_user_email [0]應該是$ unmaskd_user_email_array [0]：

$user_email       = "[email protected]" 

$unmasked_user_email_array   = explode('@', $user_email); 
$unmasked_user_email_string   = $unmasked_user_email_array[0]; 
$unmasked_user_email_string_length = strlen($unmasked_user_email_string); 

if ($unmasked_user_email_string_length > 4) { 
    $email = substr($unmasked_user_email_string, 0, -4) . '****' . $unmasked_user_email_array[1]; 
} 
else if ($unmasked_user_email_string_length < 5) { 
    $email = substr($unmasked_user_email_string, 0, -2) . '**' . $unmasked_user_email_array[1]; 
} 
else if ($unmasked_user_email_string_length < 4) { 
    $email = substr($unmasked_user_email_string, 0, -1) . '*' . $unmasked_user_email_array[1]; 
}

腓SUBSTR（）手冊：在代碼http://php.net/manual/en/function.substr.php

來源

2014-10-07 07:19:45

您可以使用SUBSTR（php.net/substr）削減字符串的結尾，然後拼接多少*你想要的。例如：

$user_email_hidden = substr($unmasked_user_email_string, 0, $unmasked_user_email_string_length-4) . '****'

來源

2014-10-07 07:17:20

他說最後3不是最後4 – 2014-10-07 07:28:00

使用php的substr方法。

Syntax : substr($string,$start,$length); 

and substr($string,$start); to get the entire string after the "$start" position(staring from 0)

參見：http://in1.php.net/substr

所以，

if ($unmasked_user_email_string_length > 4) { 

$unmasked_user_email_string with = substr($unmasked_user_email_string,0,strlen($unmasked_user_email_string)-3); 
//[email protected] => [email protected]*** 

} 

else if ($unmasked_user_email_string_length < 5) { 
//do it yourself 

} 

else if ($unmasked_user_email_string_length < 4) { 
//do it yourself 

}

來源

2014-10-07 07:19:25 khandelwaldeval

<?php 
$user_email       = "[email protected]"; 

$unmasked_user_email_array   = explode("@", $user_email); 
$unmasked_user_email_string   = $unmasked_user_email_array[0]; 
$unmasked_user_email_string_length = strlen($unmasked_user_email_string); 

if ($unmasked_user_email_string_length > 4) { 
    // replace the last three characters of $unmasked_user_email_string with *** 
    $unmasked_user_email_string = substr($unmasked_user_email_string, 0, -3) . '***'; 
} 
else if ($unmasked_user_email_string_length == 5) { 
    // replace the last two characters of $unmasked_user_email_string with ** 
    $unmasked_user_email_string = substr($unmasked_user_email_string, 0, -2) . '**'; 
} 
else if (($unmasked_user_email_string_length < 4) && ($unmasked_user_email_string_length >= 2)) { 
    // replace the last one character of $unmasked_user_email_string with * 
    $unmasked_user_email_string = substr($unmasked_user_email_string, 0, -1) . '*'; 
} 
else { 
    // replace the last one character of $unmasked_user_email_string with * 
    $unmasked_user_email_string = substr($unmasked_user_email_string, 0, -1) . '*****'; 
} 
echo $unmasked_user_email_string; 

?>

來源

2014-10-07 07:38:01

PHP替換字符串

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