PHP PDO的INSERT INTO SELECT查詢查詢不起作用

Question

$query2 = $dbs->prepare("INSERT INTO service_info(user_id) 
SELECT id 
FROM customer_info"); 

$query2 -> bindParam(':id',$_SESSION['id']); 

if($query2->execute()){ 
    return true; 
} 
else{ 
    return false; 
} 

塊引用

它不工作，爲什麼？ 我的PDO查詢是否錯誤？ 這是我的代碼在我的功能寄存器：

塊引用

public function register($firstname, $lastname, $email, $age, $contact, $gender, $password){ 

include '/include/db_config.php'; 

$query = $dbs->prepare("INSERT INTO customer_info(firstname,lastname,email,age,contact,gender,password) 
VALUES(:firstname,:lastname,:email,:age,:contact,:gender,:password)"); 


$query -> bindParam(':firstname', $firstname); 
$query -> bindParam(':lastname', $lastname); 
$query -> bindParam(':email', $email); 
$query -> bindParam(':age', $age); 
$query -> bindParam(':contact',$contact); 
$query -> bindParam(':gender',$gender); 
$query -> bindParam(':password', $password); 

if($query->execute()){ 
return true; 
} 
else{ 
return false; 
} 

$query2 = $dbs->prepare("INSERT INTO service_info(user_id) 
SELECT id 
FROM customer_info WHERE id = :user_id"); 

$query2 -> bindParam(':id',$_SESSION['user_id']); 

if($query2->execute()){ 
    return true; 
} 
else{ 
    return false; 
} 
} 

塊引用

所以這裏有什麼問題>。 < 請幫我即時乞討你們請

塊引用

Answer 1

您insert的select部分需要where條款。沒有這個，你從customer_info表中選擇並插入每個id。 bind也應該導致查詢失敗，因爲它沒有佔位符當前映射到。

嘗試（與$_SESSION['id']被映射到替換列somecolumn）：

$query2 = $dbs->prepare("INSERT INTO service_info(user_id) 
SELECT id 
FROM customer_info 
where somecolumn = :id"); 

$query2 -> bindParam(':id',$_SESSION['id']); 

if($query2->execute()){ 
    return true; 
} 
else{ 
    return false; 
} 

如果$_SESSION['id']是userid那麼你並不需要選擇的。

$query2 = $dbs->prepare("INSERT INTO service_info(user_id) values (:id)"); 

$query2 -> bindParam(':id',$_SESSION['id']); 

if($query2->execute()){ 
    return true; 
} 
else{ 
    return false; 
}