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我有方法從我的XML文件中讀取XML,我使用xpath
從XML文件中獲取元素,但總是讓我的對象爲null。 我想獲得所有的價值元素,但給我空。如何通過XPath讀取XML
,我的方法:
public ArrayList<Object> GetAnyEntity(String PathXPath) throws JAXBException {
ArrayList<Object> list = new ArrayList<Object>();
DocumentBuilderFactory domFactory = DocumentBuilderFactory.newInstance();
try {
DocumentBuilder builder = domFactory.newDocumentBuilder();
Document dDoc = builder.parse("Projects//asdad//ProjectDataBase.xml");
XPath xPath = XPathFactory.newInstance().newXPath();
NodeList nl = (NodeList)xPath.evaluate("//Project/Layer[@idLayer=2]", dDoc, XPathConstants.NODESET);
for (int i = 0; i < nl.getLength(); i++) {
list.add(nl.item(i));
}
} catch (Exception e) {
e.printStackTrace();
}
return list;
}
XML文件:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<Project xmlns="http://www.example.org/ProjectDataBase" name="name1" >
<Layer idLayer="2">
<LayerName>a</LayerName>
<Order>2</Order>
<Visible>false</Visible>
</Layer>
</Project>
你有沒有通過代碼在調試器階梯?另外,爲什麼你不包含一個標準的XML標題(指示頁面引用等)? –
我更新了我的代碼xml – MohammadTofi