JavaScript的條件爲假時可變

Question

var dayschoose = $("#days-in-park" + id).val(); // values is 3 
var storageTotalDays = localStorage.getItem("TotalDays"); //value is 12 
if (dayschoose > storageParkDays) { 
    console.log("if condition"); 
} else { 
    console.log("else conition"); 
} 

這裏3關聯的值大於12的返回假的，如果conditon但執行console.log打印（「如果條件」）不knwo爲什麼

Answer 1

嘗試使用parseInt - 見下面的代碼：

var dayschoose = parseInt($("#days-in-park" + id).val()); // values is 3 
var storageTotalDays = parseInt(localStorage.getItem("TotalDays")); //value is 12 
if (dayschoose > storageParkDays) { 
    console.log("if condition"); 
} else { 
    console.log("else conition"); 
}