我有一個應用程序here,用戶可以使用Mas的Ajax File Up-loader上傳文件。用戶必須先點擊「添加問題」按鈕來添加一行,然後才能使用文件上載器。我想知道的是,如何編碼以及在哪裏放置代碼,以便每次用戶爲每一行選擇一個文件,當用戶點擊「上傳」按鈕時,它會將文件位置插入從文本框到數據庫的那一行,但它只會這樣做,如果文件位置不在數據庫中,並且文件上傳成功了?如何在文件上載成功時插入值
我想插入'ImageFile'字段中的值和ImageId字段插入一個值時它應該添加字符串'IMG',然後字符串後面的下一個數字。例如,如果最後一個ImageId是'IMG3',那麼當插入一個值時,下一個ImageId應該是'IMG4',然後插入下一個值就意味着下一個ID是'IMG5'等。我已經連接了數據庫。
下面是PHP代碼其中包含插入值和查詢的代碼,我在那一刻:
if (isset($_POST['fileImage'])) {
$_SESSION['fileImage'] = $_POST['fileImage'];
}
if (isset($_POST['submitImageBtn'])) {
$imagequery = "SELECT ImageId, ImageFile FROM Image";
$insertimage[] = "'". mysql_real_escape_string($_SESSION['fileImage']) ."'";
$imagequery = "INSERT INTO Image (ImageId, ImageFile)
VALUES (" . implode('), (', $insertimage) . ")";
mysql_query($imagequery);
下面是它附加在文件上裝載每個錶行中,並在那裏上傳程序的代碼發生:(這是在JavaScript中,即使我知道插入值在PHP發生)
下面是PHP的頁面,它把文件上傳:
<?php
$destination_path = str_replace("//", "/", $_SERVER['DOCUMENT_ROOT']."/")."ImageFiles";
$result = 0;
$target_path = $destination_path . basename($_FILES['fileImage']['name']);
if(@move_uploaded_file($_FILES['fileImage']['tmp_name'], $target_path)) {
$result = 1;
}
sleep(1);
?>
<script language="javascript" type="text/javascript">window.top.window.stopImageUpload(<?php echo $result; ?>);</script>
<script type="text/javascript">
var sourceForm;
function insertQuestion(form) {
var $tbody = $('#qandatbl > tbody');
var $tr = $("<tr class='optionAndAnswer' align='center'></tr>");
var $image = $("<td class='image'></td>");
var $fileImage = $("<form action='imageupload.php' method='post' enctype='multipart/form-data' target='upload_target' onsubmit='startUpload(this);' class='imageuploadform' >" +
"<p class='imagef1_upload_process' align='center'>Loading...<br/><img src='Images/loader.gif' /><br/></p><p class='imagef1_upload_form' align='center'><br/><label>" +
"File: <input name='fileImage' type='file' class='fileImage' /></label><br/><label>" +
"(jpg, jpeg, pjpeg, gif, png, tif)</label><br/><br/><label>" +
"<input type='submit' name='submitBtn' class='sbtn' value='Upload' /></label>" +
"</p> <iframe class='upload_target' name='upload_target' src='#' style='wclassth:0;height:0;border:0px;solclass #fff;'></iframe></form>");
$image.append($fileImage);
$tr.append($image);
$tbody.append($tr);
}
function startUpload(imageuploadform){
$(imageuploadform).find('.imagef1_upload_process').css('visibility','visible');
$(imageuploadform).find('.imagef1_upload_form').css('visibility','hidden');
sourceForm = imageuploadform;
return true;
}
function stopUpload(success){
var result = '';
if (success == 1){
result = '<span class="msg">The file was uploaded successfully!<\/span><br/><br/>';
}
else {
result = '<span class="emsg">There was an error during file upload!<\/span><br/> <br/>' ;
}
$(sourceForm).find('.imagef1_upload_process').css('visibility','hidden');
$(sourceForm).find('.imagef1_upload_form').html(result + '<label>File: <input name="fileImage" type="file"/><\/label><br/><label>(jpg, jpeg, pjpeg, gif, png, tif)</label><br/><br/><label><input type="submit" name="submitBtn" class="sbtn" value="Upload" /><\/label>');
$(sourceForm).find('.imagef1_upload_form').css('visibility','visible');
return true;
}
</script>
哪裏是處理文件服務器端的腳本? INSERT會成功。例如,它可能出現在'if(move_uploaded_file($ _ FILES ['img'] ['tmp_name'],$ target))' – Kurt 2012-04-11 00:07:13
我更新了代碼以包含服務器端腳本,對不起回合:) – user1324106 2012-04-11 00:25:43