這是我的代碼,該upload.py HTML5上傳穆蒂文件如何使用的谷歌應用程序引擎(蟒蛇)
<form enctype="multipart/form-data" action="/" method="post">
<input type="file" name="file" multiple="true" />
<input type="submit" />
</form>
可以使用file = self.request.POST['file']
來獲得一個文件,但使用html5多文件,
如何獲得muti文件使用python時發佈?
感謝
上傳
它確定現在,按照這篇文章:Receive multi file post with google app engine
class Download_file(db.Model):
data = db.BlobProperty(required=True)
mimetype = db.StringProperty(required=True)
download_url = db.StringProperty()
class BaseRequestHandler(webapp.RequestHandler):
def render_template(self, filename, template_args=None):
if not template_args:
template_args = {}
path = os.path.join(os.path.dirname(__file__), 'templates', filename)
self.response.out.write(template.render(path, template_args))
class upload(BaseRequestHandler):
def get(self):
files=Download_file.all()
self.render_template('index.html',{'files':files})
def post(self):
files = self.request.POST.multi.__dict__['_items']
#self.response.out.write(files)
for file in files:
file=file[1]
obj = Download_file(data=file.value, mimetype=file.type)
obj.put()
file_url = "http://%s/download/%d/%s" % (self.request.host, obj.key().id(), file.filename)
file_url = "<a href='%s'>%s</a>" % (file_url,file_url,)
obj.download_url=file_url
obj.put()
self.response.out.write("Your uploaded file is now available at %s </br>" % (file_url))
class download(BaseRequestHandler):
def get(self,id,filename):
#id=self.request.get('id')
entity = Download_file.get_by_id(int(id))
self.response.headers['Content-Type'] = entity.mimetype
self.response.out.write(entity.data)
哇!這只是讓我想在週末再次開啓GAE ^^ – 2010-11-25 12:09:01