我如何讓php在我的結果中返回指定數量的字符？

Question

我試過substr（）但不能讓它工作。我只需要$ leadsmissed，$ panswerrate和$ pcloserate四捨五入到最接近的整數並顯示它。我還需要$ prevenue來顯示小數點後的兩位數字：xxx.xx

我錯過了它的語法嗎？我對這一切都很陌生。任何幫助，將不勝感激。謝謝！

<?php 
$branches = $_POST['branches']; 
$closerate = $_POST['closerate']; 
$ticketsize = $_POST['ticketsize']; 
$leadsperhour = .87; 


$revenue = ($branches * $leadsperhour) * $closerate * $ticketsize; 
$leadsmissed = $branches * $leadsperhour; 

$panswerrate = .92 * $leadsmissed; 

$pcloserate = $closerate * $leadsmissed; 
$prevenue = $pcloserate * $ticketsize; 


$result['string1'] = "Your company, on average, missed " . $leadsmissed . " leads in the past hour. "; 

$result['string2'] = "With Pronexis, you would have talked to " .  $panswerrate . " of those leads, closed " . $pcloserate . " of them, and received $" . $prevenue . " more revenue!"; 



echo json_encode($result); 
?> 

Answer 1

四捨五入爲最接近的整數：浮動與2位小數

$leadsmissed = round($leadsmissed); 
$panswerrate = round($panswerrate); 
$pcloserate = round($pcloserate); 

轉換

$prevenue = number_format($prevenue , 2);