SQL - 加入ID的所有行

Question

假設我的表如下：

id | name | country 
-------------------- 
    | John | USA 
    | Mary | USA 
    | Mike | USA 

有人能幫助我，可以添加ID的所有名的腳本？

感謝

Answer 1

試試這個

update table set a.id=b.newid from table a,(select row_number() over (order by (select null)) newid,name from #temp) b 

使訂貨一樣需要

Answer 2

-- Create a temporary table for the example. 
CREATE TABLE #People(Id int, Name nvarchar(10), Country nvarchar(10)) 

-- Insert data, leaving the Id column NULL. 
INSERT INTO #People(Name, Country) SELECT 
    'John', 'USA' UNION ALL SELECT 
    'Mary', 'USA' UNION ALL SELECT 
    'Mike', 'USA'; 

-- 1. Use Row_Number() to generate an Id. 
-- 2. Wrap the query in a common table expression (CTE), which is like an inline view. 
-- 3. If the CTE references a single table, we can update the CTE to affect the underlying table. 
WITH PeopleCte AS (
    SELECT 
     Id, 
     Row_Number() OVER (ORDER BY (SELECT NULL)) AS NewId 
    FROM 
     #People  
) 
UPDATE PeopleCte SET Id = NewId 

SELECT * FROM #People 

DROP TABLE #People