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我的應用程序處理多個請求，但我的知識會話中的規則僅由單線程執行。 例如： 線程1和線程2進入知識會話的間隙爲2millisec 但是線程1執行自己的規則，甚至線程2的規則都由線程1執行。想象一下，如果有1000個請求意味着每個請求的規則將僅由1個線程執行？在DROOLS中執行單線程？
有沒有什麼方法可以在DROOLS中防止這種情況，並確保規則由多個線程執行？
下面是一個小樣本的測試，我試過：
的Java類：
import java.math.BigDecimal;
import org.drools.KnowledgeBase;
import org.drools.KnowledgeBaseFactory;
import org.drools.builder.KnowledgeBuilder;
import org.drools.builder.KnowledgeBuilderError;
import org.drools.builder.KnowledgeBuilderErrors;
import org.drools.builder.KnowledgeBuilderFactory;
import org.drools.builder.ResourceType;
import org.drools.io.ResourceFactory;
import org.drools.runtime.StatefulKnowledgeSession;
import org.drools.runtime.rule.WorkingMemoryEntryPoint;
import org.springframework.context.support.ClassPathXmlApplicationContext;
public class DJ_Test {
public static void main(String[] args) {
try {
System.out.println("In main");
// load up the knowledge base
KnowledgeBase kbase = readKnowledgeBase();
final StatefulKnowledgeSession ksession = kbase.newStatefulKnowledgeSession();
final WorkingMemoryEntryPoint entry =ksession.getWorkingMemoryEntryPoint("RequestStream");
final Object obj_1= new Object();
Thread t1 = new Thread(){
public void run(){System.out.println(Thread.currentThread().getName() + " is running");
entry.insert(obj_1);
ksession.fireAllRules();
System.out.println(Thread.currentThread().getName() + " is terminated");
}
};
final Object obj_2= new Object();
Thread t2 = new Thread(){
public void run(){
try{
Thread.sleep(8000);
}catch(Exception e){
}
System.out.println(Thread.currentThread().getName() + " is running");
entry.insert(obj_2);
ksession.fireAllRules();
System.out.println(Thread.currentThread().getName() + " is terminated");
}
};
t1.start();
t2.start();
} catch (Throwable t) {
t.printStackTrace();
}
}
private static KnowledgeBase readKnowledgeBase() throws Exception {
/* KnowledgeBuilder kbuilder = KnowledgeBuilderFactory.newKnowledgeBuilder();
kbuilder.add(ResourceFactory.newClassPathResource("rulesFlow.bpmn"), ResourceType.BPMN2);
kbuilder.add(ResourceFactory.newClassPathResource("KansasSalesTax.drl"), ResourceType.DRL);
kbuilder.add(ResourceFactory.newClassPathResource("MissouriSalesTax.drl"), ResourceType.DRL);
kbuilder.add(ResourceFactory.newClassPathResource("SalesTax.drl"), ResourceType.DRL);
KnowledgeBuilderErrors errors = kbuilder.getErrors();
if (errors.size() > 0) {
for (KnowledgeBuilderError error: errors) {
System.err.println(error);
}
throw new IllegalArgumentException("Could not parse knowledge.");
}
KnowledgeBase kbase = KnowledgeBaseFactory.newKnowledgeBase();
kbase.addKnowledgePackages(kbuilder.getKnowledgePackages());
return kbase;*/
ClassPathXmlApplicationContext serviceContext = new ClassPathXmlApplicationContext("droolsContext.xml");
return (KnowledgeBase) serviceContext.getBean("kbase1");
}
public static class DJ_Message {
public static final int thread_1 = 1;
public static final int thread_2 = 2;
private String message;
private int status;
public String getMessage() {
return this.message;
}
public void setMessage(String message) {
this.message = message;
}
public int getStatus() {
return this.status;
}
public void setStatus(int status) {
this.status = status;
}
}
}
DRL文件
package com.sample
import com.sample.DroolsTest.Message;
//global CepService cepService;
declare Object
@role(event)
end
rule "rule_1"
salience 100
when
$o : Object() from entry-point RequestStream
then
System.out.println("Rule 1 fired by " + Thread.currentThread().getName());
Thread.sleep(5000);
end
rule "rule_2"
salience 80
when
$o : Object() from entry-point RequestStream
then
System.out.println("Rule 2 fired by " + Thread.currentThread().getName());
Thread.sleep(5000);
end
rule "rule_3"
salience 60
when
$o : Object() from entry-point RequestStream
then
System.out.println("Rule 3 fired by " + Thread.currentThread().getName());
//cepService.executingThread1();
end
rule "4"
when
Message(status == Message.GOODBYE, myMessage : message)
then
System.out.println(myMessage);
//cepService.executingThread2();
end
嗯，這不是人們要求調用的方法，而是返回所有活動會話，不是一個新的。 – nlucaroni