發送Ajax請求後,我得到一個數組作爲響應。我想在另一個函數中使用這個數組,我試圖在設置它的值之前聲明該變量而不將它放入任何函數中。Javascript在AJAX響應中聲明全局變量
var their_Info = [];
$.ajax({
url: "My PHP url",
type: "post",
data: {username:usernames} ,
success: function (response) {
their_Info = JSON.parse(response);
});
如果我想在一個單獨的功能我得到未定義使用their_Info ..
下面是引用PHP腳本:
<?php
header('Access-Control-Allow-Origin: *');
$usernames = $_POST['username'];
//$ids = join("','",$usernames);
$link = mysqli_connect("localhost", "root", "vKukRKWZRE", "table");
$acc_Info = array();
foreach ($usernames as $value) {
$query = "SELECT * FROM users WHERE username = '$value'";
$show = mysqli_query($link, $query) or die("Error");
while ($row = mysqli_fetch_array($show)) {
array_push($acc_Info, explode(',', $row['wear']));
}
}
echo json_encode($acc_Info);
?>
可能重複[如何從異步調用返回響應?](http://stackoverflow.com/questions/14220321/how-do-i-return-the-response-from-an-asynchronous-呼叫) – Andreas
你的第一個代碼中有一個右括號缺失 – Keddy1201
你試圖訪問'their_Info'的地方(和什麼時候)? –