請幫助我..我一直在努力不懈地努力,我仍然無法按照我希望的方式運行。我對編程有所瞭解。我不擅長使用方法。我在這裏有我的工作樣本,我的問題是如何獲得平均分數,以及如何在控制檯上打印它。當我運行這段代碼時,變量級中的最後一個值是控制檯上顯示的唯一值。我還需要檢查出席情況......我該怎麼做? 我需要我的決賽代碼。如何計算數組中值的平均等級?
package studentmonitoring;
import java.util。*; 公共類StudentMonitoring {
public static void main(String[] args) {
Scanner in=new Scanner(System.in);
Date date=new Date();
int[] attend1={},attend2,attend3,grade={};
String line="-------------------------------------------------------------------";
String[] idNum1={},idNum2={},gender={}, name1={},name2={},name3={},name4={},address={},sub={};
掃描儀輸入=新掃描儀(System.in); int check = 0,num = 0;
System.out.println(line);
System.out.println("\t\t****STUDENT MONITORING****");
System.out.println(line);
System.out.println("\nGood day teacher, to start using this program input the following information first.\n");
System.out.println(line);
System.out.print("NAME OF SCHOOL: ");
String sName=in.nextLine();
System.out.print("ADDRESS OF SCHOOL: ");
String sAdd=in.nextLine();
System.out.print("SCHOOL IDENTIFICATION NUMBER: ");
String sId=in.nextLine();
System.out.println(line);
System.out.println("STUDENTS INFORMATION");
System.out.println("Enter the year and section of this class");
String yearSec=in.nextLine();
System.out.println("How many student information do you want to input? ");
int numberStudents=in.nextInt();
idNum1=new String[numberStudents];
name1=new String[numberStudents];
name2=new String[numberStudents];
name3=new String[numberStudents];
name4=new String[numberStudents];
attend1=new int[200];
attend2=new int[200];
attend3=new int[200];
address=new String[numberStudents];
grade=new int[100];
gender=new String[numberStudents];
idNum2=new String[numberStudents];
System.out.println("Enter the number of subjects you have: ");
int numSub=in.nextInt();
sub=new String[numSub];
in.nextLine();
for(int x=0;x<numSub;x++) {
System.out.print("SubjeC#"+(x+1)+": ");
sub[x]=in.nextLine();
}
for(int x=0;x<numberStudents;x++) {
in.nextLine();
System.out.println(line);
System.out.println("Student #"+(x+1));
System.out.print("LAST NAME: ");
name1[x]=in.nextLine();
System.out.print("FIRST NAME: ");
name2[x]=in.nextLine();
System.out.print("MIDDLE INITIAL: ");
name3[x]=in.nextLine();
System.out.print("GENDER: ");
gender[x]=in.nextLine();
System.out.print("ADDRESS: ");
address[x]=in.nextLine();
System.out.print("ID NUMBER: ");
idNum1[x]=in.nextLine();
System.out.println(line);
System.out.println("Enter the grades here.");
System.out.println(line);
for (int a=0;a<numSub;a++) {
System.out.print(sub[a]+": ");
grade[a]=in.nextInt();
}
}
System.out.println("This is the list of the students info you've inputted.");
System.out.println("ID Number\t Name\t\t GENDER\t\t ADDRESS");
for(int x=0;x<numberStudents;x++) {
System.out.println(idNum1[x]+"\t\t"+name1[x]+" "+name2[x]+","+name3[x]+".\t\t"+gender[x]+"\t\t"+address[x]);
}
System.out.println("Subject\t\tGrades");
for(int x=0;x<numSub;x++) {
System.out.println(sub[x]+"\t\t"+grade[x]);
}
System.out.println(line);
System.out.println();
}
}
這個並行陣列設計不好。 – Enzokie
請幫助我做出更好的一個。 – JohnHERE
如果您已經開始使用OOP,則應該將其設計爲一個Student對象數組,而不是爲每個屬性創建一個單獨的數組。 – Enzokie