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我正在向PHP文件提交表單,該表單會從數據庫返回一些產品。我現在需要添加一個淘汰賽模板與返回的數據。這裏是代碼:從javascript文件中剔除js模板
$("#search-filter-form").submit(function(event) {
// stop form from submitting normally
event.preventDefault();
// get some values from elements on the page:
var $form = $(this),
url = $form.attr('action');
// Send the data using post
var posting = $.post(url,
{ place: searchFilterViewModel.searchFilterAutoComplete.placeObject,
categories: searchFilterViewModel.categorySelect.selectedCategories
}).done(function(data) {
searchResultsViewModel.allProducts(JSON.parse(data));
for(var x = 0; x < searchResultsViewModel.allProducts().length; x++) {
$("search-results").append();// NEED TO APPEND THE KNOCKOUT TEMPLATE HERE
}
});
});
我想有一個單獨的文件與html模板。我創造了這個示例文件:
product_template.html:
<script type="text/html" id="product-template">
<h3 data-bind="text: allProducts.name"></h3>
<p>Credits: <span data-bind="text: credits"></span></p>
</script>
如何獲得該模板文件打印出來,從上面的javascript函數內?