什麼錯誤它顯示的錯誤如下圖所示,當IM網絡上運行它..PHP:在那裏
"Parse error: syntax error, unexpected 'else' (T_ELSE) in C:\xampp\htdocs\trial\checkadd.php on line 30"
我不知道什麼是對的錯誤..
即時通訊使用phpmyadmin
到存儲在數據庫中,但圖像不能在網上..我不知道從PHP或SQL ..錯誤的PHP錯誤幫助我找到它..我也添加我的PHP編碼,顯示錯誤here..pls看看..在此先感謝
<?php
$host="localhost"; // Host name
$username="root"; // Mysql username
$password=""; // Mysql password
$db_name="MMDB"; // Database name
$tbl_name="artist"; // Table name
// Create connection
$conn = mysqli_connect($host, $username, $password, $db_name);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$Name=$_POST['Name'];
$Hometown=$_POST['Hometown'];
$Income=$_POST['Income'];
$Image=$_POST['Image'];
//$file =$_FILES['image']['tmp_name'];
$Video=$_POST['Video'];
$sql = "INSERT INTO $tbl_name (Name, Hometown, Income, Image, Video)
VALUES ('$Name', '$Hometown', '$Income', 'Image','$Video')";
$sql = "(SELECT $tbl_name FROM artist WHERE id=file)" ;
if (mysqli_query($conn, $sql)); {
include 'admin.php';
} else {
echo "x";
}
mysqli_close($conn);
?>
難道我的回答解決問題的嗎? – Tristup 2014-12-06 07:25:21