從encodeing ANSI轉換所有CSV文件使用python

Question

我有如下的Python代碼爲utf8：

import os 
from os import listdir 

def find_csv_filenames(path_to_dir, suffix=".csv"): 
    filenames = listdir(path_to_dir) 
    return [ filename for filename in filenames if filename.endswith(suffix) ] 
    #always got the error this below code 
filenames = find_csv_filenames('C:\casperjs\project\teleservices\csv') 
for name in filenames: 
    print name 

我遇到了錯誤：

filenames = find_csv_filenames('C:\casperjs\project\teleservices\csv') 
Error message: `TabError: inconsistent use of tabs and spaces in indentation` 

我需要：我想讀的所有CSV文件並將其從編碼ansi轉換爲utf8，但上面的代碼只是每個csv文件的讀取路徑。我不知道它有什麼問題嗎？

Answer 1

以下會將每一行轉換爲ASCII文件：

import os 
from os import listdir 

def find_csv_filenames(path_to_dir, suffix=".csv"): 
    path_to_dir = os.path.normpath(path_to_dir) 
    filenames = listdir(path_to_dir) 
    #Check *csv directory 
    fp = lambda f: not os.path.isdir(path_to_dir+"/"+f) and f.endswith(suffix) 
    return [path_to_dir+"/"+fname for fname in filenames if fp(fname)] 

def convert_files(files, ascii, to="utf-8"): 
    for name in files: 
     print "Convert {0} from {1} to {2}".format(name, ascii, to) 
     with open(name) as f: 
      for line in f.readlines(): 
       pass 
       print unicode(line, "cp866").encode("utf-8")  

csv_files = find_csv_filenames('/path/to/csv/dir', ".csv") 
convert_files(csv_files, "cp866") #cp866 is my ascii coding. Replace with your coding. 

Answer 2

參考文獻：http://docs.python.org/2/howto/unicode.html

如果你需要一個字符串，說它存儲爲小號，要編碼爲特定的格式，可以使用s.encode（）

Answer 3

您的代碼只是列出了csv文件。它沒有做任何事情。如果您需要閱讀它，可以使用csv模塊。如果你需要管理編碼，你可以這樣做：

import csv, codecs 
def safe_csv_reader(the_file, encoding, dialect=csv.excel, **kwargs): 
    csv_reader = csv.reader(the_file, dialect=dialect, **kwargs) 
    for row in csv_reader: 
     yield [codecs.decode(cell, encoding) for cell in row] 

reader = safe_csv_reader(csv_file, "utf-8", delimiter=',') 
for row in reader: 
    print row