我已經創建了一個表單,其中包含用戶的姓名,聯繫電話號碼,照片ID號碼,工作資料等信息。一旦輸入所有信息,它就會存儲在數據庫中。當他第二次登錄時,在輸入照片身份證號碼後,全部信息應顯示在表格上,無需輸入。我正在使用鍵入事件。我曾嘗試這個代碼,但它拋出異常,因爲java:輸入id後應顯示全部信息
值java.sql.SQLException:在結果的開始時設置
public void show()
{
try
{
String id=photo_id_num.getText();
System.out.println(""+id);
Connect c=new Connect();
con=c.getConnection();
Statement stmt=con.createStatement();
String queryPhotoid = "select * from tbl_visitor ";
ResultSet rs1= stmt.executeQuery(queryPhotoid);
while (rs1.next())
{
if(id.equals(rs1.getString(6)))
{
// Read values using column name
String name = rs1.getString(2);
int contno = rs1.getInt(3);
String orgname = rs1.getString(4);
String jobpro = rs1.getString(5);
String category = rs1.getString(7);
String date = rs1.getString(8);
int noofpeople = rs1.getInt(9);
Blob image = rs1.getBlob(10);
int extrapeople = rs1.getInt(11);
System.out.println("Name:"+name+" Contact_no:"+contno+"Org_Name:"+orgname+" Job_profile:"+jobpro+"Category:"+category+"Date:"+date+"No_Of_People:"+noofpeople+"image:"+image+"Having extra people:"+extrapeople);
}
}
}
catch (SQLException sqlEx)
{
sqlEx.printStackTrace();
}
}
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'catch(SQLException sqlEx){..'應該是'catch(SQLException sqlEx) {sqlEx.printStackTrace(); ..' –