2016-06-27 236 views
-6

我得到這個錯誤在一個簡單的登錄我開發:致命錯誤:未捕獲的錯誤

Fatal error: Uncaught Error: Call to undefined function mysql_fetch_array() in D:\xampp\htdocs\script\login.php:18 Stack trace: #0 {main} thrown in D:\xampp\htdocs\script\login.php on line 18

所以,這是我的login.php:

<?php 
require "banco.php"; 
session_start(); 
$login = isset($_POST["login"]) ? addslashes(trim($_POST["login"])) : FALSE; 
$senha = isset($_POST["senha"]) ? md5(trim($_POST["senha"])) : FALSE; 
if(!$login || !$senha){ 
    echo "Você deve digitar sua senha e login!"; 
    exit;} 
$SQL = "SELECT id, nome, login, senha FROM usuario WHERE login = '$login' "; 
$result_id = $db->query($SQL);// or die("Erro no banco de dados!"); 
$total = $result_id->fetchColumn(); 
if($total){ 
    $dados = @mysql_fetch_array($result_id); 
if(!strcmp($senha, $dados["senha"])){ 
    $_SESSION["id_usuario"]= $dados["id"]; 
    $_SESSION["nome_usuario"] = stripslashes($dados["nome"]); 
    header("Location: index.php"); 
exit;} 
else{ 
    echo "Senha inválida!"; 
exit;} 

如何解決這個?不管怎麼說,還是要謝謝你!

+0

您使用的是PHP7嗎? mysql已經在PHP7中被移除,轉而使用MySQLi – zanderwar

+2

閱讀[this](https://stackoverflow.com/tags/pdo/info)瞭解如何使用PDO – hjpotter92

+0

檢查http://www.sathyabaman.com/2016/ 05/16/pdo-database-insert-script-php/ –

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