如何替換每行文本文件中的內容？

Question

我在Notepad ++文件中使用以下格式的一堆行。

目前的格式如下：

Line 1:  2017-05-26 02:26:40,362 Executing SQL query [ Select * from T1 ] 
Line 2:  2017-05-26 02:26:40,362 Executing SQL query [ Select * from T2 ] 
Line 3:  2017-05-26 02:26:40,362 Executing SQL query [ Select * from T3 ] 
Line 4:  2017-05-26 02:26:40,362 Executing SQL query [ Select * from T1 ] 

在每一行預期的結果是經過如下替換：

Select * from T1 
Select * from T2 
Select * from T3 
Select * from T1 

我還需要預期的結果在下面的格式，以及：

2017-05-26 02:26:40,362  Select * from T1 
2017-05-26 02:26:41,367  Select * from T2 
2017-05-26 02:26:45,762  Select * from T3 

如何在Notepad ++中實現它？

Answer 1

您可以用替換窗口中的空字符串（Ctrl+H）替換正則表達式^.*\[ | \].*$的匹配項。只要確保您的搜索模式設置爲Regular expression。

Answer 2

import re 

txt = ''' 
Line 1:  2017-05-26 02:26:40,362 Executing SQL query [ Select * from T1 ] 
Line 2:  2017-05-26 02:26:40,362 Executing SQL query [ Select * from T2 ] 
Line 3:  2017-05-26 02:26:40,362 Executing SQL query [ Select * from T3 ] 
Line 4:  2017-05-26 02:26:40,362 Executing SQL query [ Select * from T1 ] 
''' 

txt_new = [re.findall(r'(Select \* from T[0-9]+)', i)[0] for i in txt.split('\n') if i] 
print(txt_new)