查詢改進：foreach

Question

我有以下模型函數，我想知道如何改進它，並在需要時拉出需要的$row，這樣我就不會收到PHP錯誤。

如何，我拉着所需的數據：

$data['companyName'] = $this->core_model->companyDetails('coreCompanyName'); 

錯誤：

Undefined property: stdClass::$coreContactName 
Undefined property: stdClass::$coreContactEmail 

型號：

function companyDetails() 
{ 
    $this->db->select('coreCompanyName, coreContactName, coreContactEmail'); 

    $this->db->from('core'); 

    $whereData = array('coreCompanyName' => $companyName, 'coreContactName' => $companyContactName, 'coreContactEmail' => $companyContactEmail); 

    $this->db->where($whereData); 

    $query = $this->db->get(); 

    $result = ''; 

    if ($query->num_rows() > 0) 
    { 

     foreach ($query->result() as $row) 
     { 
      $result .= $row->coreCompanyName; 
      $result .= $row->coreContactName; 
      $result .= $row->coreContactEmail; 
     } 
    } 
    return $result; 
} 

Answer 1

<?php 

/** 
* 
* WHERE ARE : $companyName, $companyContactName, $companyContactEmail being defined ? 
* WHY return 'companyName' WHEN You are quering based on the '$companyName' ??? 
* Your query wil fail with out it, that that's all your using ? 
* 
*/ 
function companyDetails() { 

    $query = $this->db->query("SELECT companyName FROM core WHERE coreCompanyName = ? AND coreContactName = ? AND coreContactEmail = ? LIMIT 1", 
    array($companyName, $companyContactName, $companyContactEmail)); 
    return ($query->num_rows() == 1) ? $query->row()->companyName : FALSE; 

} 

Answer 2

IT方面HOULD是這樣

$this->db->select('coreCompanyName, coreContactName, coreContactEmail'); 

不

$this->db->select('coreCompanyName','coreContactName','coreContactEmail'); 

參見參考http://codeigniter.com/user_guide/database/active_record.html#select

要限制到一組特定的記錄，使用其中（）函數。例如

$this->db->where('companyId', $companyId); 

Answer 3

變化：

$this->db->select('coreCompanyName','coreContactName','coreContactEmail'); 

要：

$this->db->select('coreCompanyName, coreContactName, coreContactEmail'); 

現在，你說的這個拉的所有數據，但實際上並沒有過濾的結果。我不知道需要的數據是什麼